Nothing is less dense than gas. gas is the least dense form of matter.
You can form 9.20 L of NH₃ gas at 93.0 °C and 37.3 kPa or 2.56 L at STP. The balanced chemical equation is N₂ + 3H₂ → 2NH₃ Since all substances are gases, we can use litres instead of moles in our calculations. You don't specify the pressure and temperature of the NH₃, so I will calculate its volume in two ways.
<span>Barium - A) Great conductor of heat and electricity
Potassium - B) Malleable and highly reactive
Boron - C) Has properties of both metals and nonmetals
Neon - D) Nonreactive gas
Let's look at each element and it's place on the periodic chart to see what matches.
Potassium - This is on the far left column for alkali metals. This means it's highly reactive and since it's a metal, it's both malleable and conductive. Looking at the available options, "B) Malleable and highly reactive" is the best choice.
Barium - This element is in the second column from the left, so it's a fairly reactive metal, but not nearly as reactive as Potassium above. So "A) Great conductor of heat and electricity" is the best choice here, although I wouldn't call it "great". The resistivity of barium is about 20 times larger than copper.
Boron - This element is about in the middle of the periodic chart, so it does have the properties of both metals and nonmetals. So "C) Has properties of both metals and nonmetals" is the best choice.
Neon - This is in the far right column for noble gasses. Very non-reactive. So "D) Nonreactive gas" is the best choice.</span>
Answer:
0.22M
Explanation:
We will be using the law of dilutions. We are simply increasing the amount of solvent to create a larger volume of solution.
So: moles before dilution = moles after dilution & 
. And M = moles/liter of solution, so if we express this as moles = M x 
.
That is how we derive the formula we will be using: 
or
Applying this formula to our problem, we can substitute the variables with the given values to find the molarity of the dilute solution.
M1 = 3.5M
V1 = 18.8mL
M2 = ?
V2 = 296.6mL
Equation: (3.5M)(18.8mL) = (296.6mL)(M2)
==> 65.8M*mL = 296.6mL * M2
==> M2 = (65.8 M*mL)/296.6mL
==> M2 = 0.22M
