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drek231 [11]
3 years ago
5

Balance this chemical equation. NH4OH AlCl3 → Al(OH)3; NH4Cl

Chemistry
2 answers:
skad [1K]3 years ago
7 0
3NH4OH+AlCl3=Al(OH)3+3NH4Cl
DedPeter [7]3 years ago
5 0

Explanation:

When the number of atoms on both reactant and product side are equal the this chemical equation is known as balanced chemical equation.

For example, NH_{4}OH + AlCl_{3} \rightarrow Al(OH)_{3} + NH_{4}Cl

Number of atoms on reactant side are as follows.

  • N = 1
  • H = 5
  • O = 1
  • Al = 1
  • Cl = 3

Number of atoms on product side are as follows.

  • N = 1
  • H = 7
  • O = 3
  • Al = 1
  • Cl = 1

Therefore, to balance this chemical equation we multiply NH_{4}OH by 3 on reactant side and multiply NH_{4}Cl by 3 on product side.

Hence, the balanced chemical reaction equation is as follows.

    3NH_{4}OH + AlCl_{3} \rightarrow Al(OH)_{3} + 3NH_{4}Cl

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A piece of unknown metal with mass 30 g is heated to 110.0 °C and dropped into 100.0 g of water at 20.0 °C. The final temperatur
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<u>Answer:</u> The specific heat of metal is 0.821 J/g°C

<u>Explanation:</u>

When metal is dipped in water, the amount of heat released by metal will be equal to the amount of heat absorbed by water.

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]       ......(1)

where,

q = heat absorbed or released

m_1 = mass of metal = 30 g

m_2 = mass of water = 100 g

T_{final} = final temperature = 25°C

T_1 = initial temperature of metal = 110°C

T_2 = initial temperature of water = 20.0°C

c_1 = specific heat of metal = ?

c_2 = specific heat of water = 4.186 J/g°C

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Hence, the specific heat of metal is 0.821 J/g°C

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