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3 years ago

What is shown in the diagram?

Chemistry

2 answers:

notka56 [123]3 years ago

6 0

Answer:

generator

Explanation:

i took the test

lukranit [14]3 years ago

4 0

Its a Generator

It generates an electrical current using a battery.

A motor generates a mechanical current that you have to physically generate yourself.

Hope this helps! :)

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If the north and south ends of separate magnets are interacting they will...

Dmitrij [34]

A. They will Attract to each other

3 0

3 years ago

Calculate the density of the aluminum cylinder with a diameter 0f 1.3 cm weighing 18 grams. Height of the cylinder is 5.2 Cm. Fi

Masja [62]

Answer:

Percent error = 3.7%

Explanation:

Given data:

Density of Al cylinder = ?

Weight of cylinder = 18 g

Diameter = 1.3 cm

Height = 5.2 cm

Actual density of Al = 2.7 g/cm³

Percent error = ?

Solution:

First of all we will calculate the volume of cylinder through given formula.

V = πr²h

r = diameter /2

V = 22/7 × (0.65 cm)²× 5.2 cm

V = 22/7 × 0.4225cm²× 5.2 cm

V = 6.89 cm³

Now we will calculate the density.

d = m/v

d = 18 g/ 6.89 cm³

d = 2.6 g/cm³

Percent error:

Percent error = measured value - actual value /actual value × 100

Percent error = 2.6g/cm³ - 2.7g/cm³ /2.7g/cm³ × 100

Percent error = 3.7%

Negative sign shows that measured or experimental value is less than actual value.

6 0

3 years ago

State two differences between an element and a compound.

Umnica [9.8K]

Answer:

See the picture... I hope that's the answer

7 0

3 years ago

Substance X is a compound containing 632mg of manganese and 368mg of oxygen. Substance X is shown

defon

The empirical formula : MnO₂.

<h3>Further explanation</h3>

Given

632mg of manganese(Mn) = 0.632 g

368mg of oxygen(O) = 0.368 g

M Mn = 55

M O = 16

Required

The empirical formula

Solution

You didn't include the pictures, but the steps for finding the empirical formula are generally the same

Find mol(mass : atomic mass)

Mn : 0.632 : 55 = 0.0115

O : 0.368 : 16 =0.023

Divide by the smallest mol(Mn=0.0115)

Mn : O =

$\tt \dfrac{0.0115}{0.0115}\div \dfrac{0.023}{0.0115}=1\div 2$

The empirical formula : MnO₂

8 0

3 years ago

The volume of CO2 at 99.3 kPa was measured at 455 cm3. What will the volume be if the pressure is adjusted to 202.6 kPa?

Marizza181 [45]

Answer:

<h3>The answer is 223.0 cm³</h3>

Explanation:

To find the volume when the pressure is at 202.6 kPa we use Boyle's law which is

$P_1V_1 = P_2V_2$

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the final volume

$V_2 = \frac{P_1V_1}{P_2} \\$

From the question

P1 = 99.3 kPa = 99300 Pa

V1 = 455 cm³

P2 = 202.6 kPa = 202600

So we have

$V_2 = \frac{99300 \times 455}{202600} = \frac{45181500}{202600} \\ = 223.008390...$

We have the final answer as

Hope this helps you

6 0

4 years ago