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marissa [1.9K]
2 years ago
15

How many miles is a light year

Physics
2 answers:
Stells [14]2 years ago
6 0

Answer:

5,878,625,370,000 miles or 5.87 Trillion miles

Explanation:

The result: One light-year equals 5,878,625,370,000 miles (9.5 trillion km).

Marrrta [24]2 years ago
6 0

One light-year equals 5,878,625,370,000 miles (9.5 trillion km)

explanation: To find the distance of a light-year, you multiply this speed by the number of hours in a year (8,766).

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A brick of mass 1.15 kg is attached to a thin (massless) cable and whirled around in a circle in a vertical plane. The circle ha
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Explanation:

It is given that,

Mass of the brick, m = 1.15 kg

Radius of the circle, r = 1.44 m

The cable will break if the tension exceeds 43.0 N

Let v is the maximum sped can have at the bottom of the circle before the cable will break. At the bottom of the circle, the net force is equal to the centripetal force along with the weight of the brick. So,

T=\dfrac{mv^2}{r}+mg

\dfrac{T}{m}-g=\dfrac{v^2}{r}

v=\sqrt{(\dfrac{T}{m}-g)r}

v=\sqrt{(\dfrac{43}{1.15}-9.8)\times 1.44}

v = 6.30 m/s

So, the maximum speed of the brick at the bottom of the circle before the cable will break is 6.3 m/s. Hence, this is the required solution.

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3 years ago
A 4.00-kg block is attached to a vertical rod by means of two strings. when the system rotates about the axis of the rod, the st
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3 years ago
How much heat is required to convert 2.55g of water at 28 degrees c to steam?
pantera1 [17]
There are two different processes here:
1) we must add heat in order to bring the temperature of the water from 28^{\circ}C to 100^{\circ}C (the temperature at which the water evaporates)
2) other heat must be added to make the water evaporates

1) The heat needed for process 1) is
Q_1=m C_s \Delta T
where 
m=2.55 g is the water mass
C_s = 4.18 g/J^{\circ}C is the water specific heat
\Delta T=100^{\circ}C-28^{\circ}C=72^{\circ}C is the variation of temperature of the water
If we plug the numbers into the equation, we find
Q_1 = (2.55 g)(4.18 J/g^{\circ}C)(72^{\circ}C)=767.4 J

2) The heat needed for process 2) is
Q=m L_e
where 
m=2.55 g is the water mass
L_e = 2264.7 J/g is the latent heat of evaporation of water
If we plug the numbers into the equation, we find
Q_2=(2.55 g)(2264.7 J/g)=5775.0 J

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3 years ago
1Which of the following components of blood would you expect to see in higher
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A cube, whose edges are aligned with the , and axes, has a side length . The field is immersed in an electric field aligned with
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Complete Question

Complete Question is attached below

Answer:

q=1.558*10^{-9}c

Explanation:

From the question we are told that:

Side length s=1.13m

Left field strength E_l=784.75N/m

Right field strength E_r=776.38 N/m

Front field strength E_f=725.5 N/m

Back field strength E_b=749.54 N/m

Top field strength E_t=944.95 N/m

Bottom field strength E_{bo}=1082.58 N/m

Generally, the equation for  Charge flux is mathematically given by

\phi=EAcos\theta

Where

Theta for Right,Left,Front and Back are at an angle 90

cos 90=0

Therefore

\phi =0 with respect to Right,Left,Front and Back

Generally, the equation for  Charge Flux is mathematically also given by

\phi=\frac{q}{e_o}

Where

Area =L*B\\\\A=1.13*1.13\\\\A=1.2769m^2

Therefore

Q_{net}=E_{bo}Acos\theta_{bo} +E_tAcos\theta_t

Q_{net}=1082.85*1.2769*cos0=944.95*1.2769cos (180)

Q_{net}=176N/C m^2

Giving

q=\phi*e_0

q=176N/C m^2*1.558*10^{-12}c

q=1.558*10^{-9}c

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2 years ago
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