<h2>
Answer:</h2>
(a) positively charged
<h2>
Explanation:</h2>
Let's take the scenario step by step
(i) Carbon-10 with 6 protons and 4 neutrons. i.e
¹⁰₆C
(ii) Undergoes a radioactive beta decay (β) decay to form Boron-10 with 5 protons and 5 neutrons ¹⁰₅B as follows;
¹⁰₆C => ¹⁰₅B + β -----------------------(i)
<em>Remember that;</em>
β decay can either be β- or β+
Where;
β - = ⁰₋₁ e⁻ (called electron and is negatively charged)
β + = ⁰₁ e⁺ (called positron and is positively charged)
Now, to balance the equation (i) above, β+ has to be used as follows;
¹⁰₆C => ¹⁰₅B + ⁰₁ e⁺
Therefore, the additional particle produced during this decay is ⁰₁ e⁺ (called positron and is positively charged)
