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lesya692 [45]
3 years ago
11

A 4.00-kg block is attached to a vertical rod by means of two strings. when the system rotates about the axis of the rod, the st

rings are extended as shown in fig. p5.104 and the tension in the upper string is 80.0 n. (a) what is the tension in the lower cord? (b) how many revolutions per minute does the system make? (c) find the number of revolutions per minute at which the lower cord just goes slack. (d) explain what happens if the number of revolutions per minute is less than that in part (c).
Physics
1 answer:
Alina [70]3 years ago
3 0
Https://answers.yahoo.com/question/index?qid=20130908151723AA4vGjO

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A baseball is hit at ground level. The ball reaches its maximum height above ground level 3.0 s after being hit. Then 2.5 s afte
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Answer:

Part a)

H = 44.1 m

Part b)

y = 13.48 m

Part c)

d = 8.86 m

Explanation:

Part a)

As we know that ball will reach at maximum height at

t = 3 s

now we will have

t = \frac{v sin\theta}{g}

now we have

3 = \frac{vsin\theta}{9.8}

v sin\theta = 29.4 m/s

Now maximum height above ground is given as

H = \frac{v^2sin^2\theta}{2g}

H = \frac{29.4^2}{2(9.8)}

H = 44.1 m

Part b)

Height of the fence is given as

y = (vsin\theta) t - \frac{1}{2}gt^2

y = (29.4)(5.5) - \frac{1}{2}(9.8)(5.5^2)

y = 13.48 m

Part c)

As we know that its horizontal distance moved by the ball in 5.5 s is given as

x = v_x t

97.5 = v_x (5.5)

v_x = 17.72 m/s

now total time of flight is given as

T = 3 + 3 = 6 s

so range is given as

R = v_x T

R = (17.72)(6)

R = 106.4 m

so the distance from the fence is given as

d = 106.4 - 97.5

d = 8.86 m

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Answer:

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We take the derivative of Ohm's law with respect to time: V = IR
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