1 year ago

Which of the following is not an SI unit. A. pound B. Newton C. Meter D. kilogram

Physics

1 answer:

Hunter-Best [27]1 year ago

3 0

Answer:

pound

Explanation:

Pound is an SAE or imperial unit not SI

You might be interested in

Calcula la resistencia de un conductor de cobre de 2 m de longitud y 0,1 m2 de sección. Resistividad del Cu = 1,7 · 10–8 Ω · m

Fudgin [204]

Answer:

an expression of more than two algebraic terms, especially the sum of several terms that contain different powers of the same variable(s).

5 0

2 years ago

What colors form the spectrum of visible light

Law Incorporation [45]

Red, orange, yellow, green, blue, indigo, violet :)

3 0

3 years ago

Question 3 of 10

Fynjy0 [20]

Answer: D

Explanation: a p e x :)

5 0

2 years ago

Read 2 more answers

A solid, cylindrical wire conductor has radius R = 30 cm. The wire carries a current of 2.0 A which is uniformly distributed ove

blondinia [14]

Answer:

Explanation:

The point at which magnetic field is to be found lies outside wire so while applying Ampere's law we shall take the whole of current . If B be magnetic field which is circular around conductor.

Applying Ampere's law :-

∫ B dl = μ₀ I ; I is current passing through ampere's loop

B x 2π x 2.00 = 4 x π x 10⁻⁷ x 2

B = 2 x 10⁻⁷ T.

7 0

2 years ago

A positive test charge q is released from rest at distance r away from a charge of Q and a distance 2r away from a charge of 2Q.

Luba_88 [7]

Answer: Option (b) is the correct answer.

Explanation:

It is given that a positive test charge q is released from rest at a distance r away from a charge of +Q and a distance 2r which is away from a charge of +2Q.

Then test charge to the right immediately after being released.

Therefore, the net force will be as follows.

F = $\frac{kqQ}{r^{2}} - kq\frac{(2Q)}{(2r)^{2}}$

= $\frac{4KqQ - 2KqQ}{4r^{2}}$

= $\frac{KqQ}{2r^{2}}$

F = $\frac{KqQ}{2r^{2}}$ > 0

Thus, we can conclude that the test charge move to the right immediately after being released.

7 0

2 years ago