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2 years ago

Jake said he can find 630 ÷ 10 by taking the 0 off of 630 to get 63.

Mathematics

1 answer:

Colt1911 [192]2 years ago

4 0

Answer:

Jake is incorrect with his methodology for solving these problems

Step-by-step explanation:

Jake is incorrect with his methodology for solving these problems. This is because dividing a number by 10 requires moving the decimal point one digit to the left. When dividing 630 by 10, removing the zero works because by moving the decimal one digit to the left we would simply drop the zero and the decimal would not be needed leaving the answer as 63. However, this does not work on numbers that already have a decimal such as 35.270. This number divided by 10 would be 3.527 but simply removing the 0 like Jake states would give us the incorrect answer of 35.27

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The advertising department of a nationally circulated magazine wishes to estimate the mean age of its subscribers within 0.5 yea

zhenek [66]

Answer: Option 'd' is correct.

Step-by-step explanation:

Since we have given that

Margin of error = 0.5 years

Standard deviation = 5

At 90% confidence, z = 1.645

We need to find the minimum size of the sample they must take.

So,

$n=(\dfrac{z\sigma}{E})^2\\\\n=(\dfrac{1.645\times 5}{0.5})^2\\\\n=270.6\\\\n\approx 271$

Hence, Option 'd' is correct.

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3 years ago

⦁ To the nearest tenth, find the perimeter of ∆ABC with vertices A(2,4), B(-2,1) and C(2,1). Show your work.

Colt1911 [192]

We need the length of the sides.
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3 years ago

Your city is having a sneaker convention! A pair of Ground Morgans is 20% less expensive than a pair of Elite Butterflies, Elite

Amanda [17]

Answer:

Ground Morgans are 52% the price of Floating Jumps.

Step-by-step explanation:

A pair of Ground Morgans $GM$ is 20% less expensive than a pair of Elite Butterflies $EB$ , this means

$GM= 0.8 EB$ (GM is 80% the price of EB's)

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$EB =1.3 CT$ (EM's is 130% the price of CT's)

Cloud Trainers $CT$ are 50% less expensive than Floating Jumps $FJ$ , this means

$CT=0.5FJ$ (CT is 50% the price of FJ)

Now, if we want the price of Ground Morgans in terms of Floating Jumps, then, since EB = 1.3 CT,

$GM=0.8 (1.3CT)$

and since CT = 0.5F, we have

$GM = 0.8(1.3(0.5FJ))$ .

Simplifying we get

$\boxed{GM =0.52FJ}$

Ground Morgans are 52% the price of Floating Jumps.

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3 years ago

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AnnyKZ [126]

The answer is

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3 years ago

Read 2 more answers

Suppose that 10% of all homeowners in an earthquake-prone area of California are insured against earthquake damage. Four homeown

guapka [62]

Remainder of question:

Find the probability distribution of x

Answer:

The random variable x is defined as: X = {0, 1, 2, 3, 4}

The probability distribution of X:

P(X = 0) = 0.656

P(X = 1) = 0.2916

P(X= 2) = 0.0486

P(X=3) = 0.0036

P(X = 4) = 0.0001

Step-by-step explanation:

Sample size, n = 4

Random variable, X = {0, 1, 2, 3, 4}

10% (0.1) of the homeowners are insured against earthquake, p = 0.1

Proportion of homeowners who are not insured against earthquake, q = 1 - 0.1

q = 0.9

Probability distribution of x,

$P(X = r) = ^nC_r *p^r q^{n-r} \\\\P(X= 0) =(^4C_0 *p^1 q^4 )\\P(X=0) = (^4C_0 *0.1^0 0.9^4 ) = 0.656\\P(X= 1)= (^4C_1 *p^1 q^3 )\\P(X=1) = (^4C_1 *0.1^1 0.9^3 ) = 0.2916\\P(X= 2)=( ^4C_2 *p^2 q^2) \\P(X=2) = (^4C_2 *0.1^2 0.9^2 ) = 0.0486\\P(X= 3) = (^4C_3 *p^3 q^3) \\ P(X=3) = (^4C_3 *0.1^3 0.9^1 ) = 0.0036\\P(X= 4) = (^4C_4 *p^4 q^0 )\\ P(X=4) =(^4C_4 *0.1^4 0.9^0 ) = 0.0001$

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3 years ago