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pickupchik [31]
2 years ago
11

Can someone explain to me how to do this? I just don't get it.

Mathematics
1 answer:
Maksim231197 [3]2 years ago
7 0

Answer:

x=130

Step-by-step explanation:

triangle=180

180-34-96=50

line=180

180-50=130

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Un número multiplicado 2 veces que me de 4633
lions [1.4K]

Answer:

2316

Step-by-step explanation:

divide 4633 por 2 y la respuesta es 2316 (no abra el enlace, te lleva a un sitio inapropiado)

3 0
3 years ago
Help me solve this problem please
lara31 [8.8K]

Answer:

CD = 45

Step-by-step explanation:

CE = 180

( x + 6 ) + ( 4x - 21 ) = 180

5x - 15 = 180

5x = 195

x = 39

substitute x in CD

CD = x + 6

CD = 39 + 6

CD = 45

5 0
2 years ago
There are 36 people waiting in line for hayride only six people can ride on each wagon if each wagon is full how many wagons are
ANEK [815]

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Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
Type the correct answers out, thank you - 20 POINTS
nadezda [96]
AB and BC form a right angle at their point of intersection. This means AB is perpendicular to BC.

We are given the coordinates of points A and B, using which we can find the equation of the line for AB.

Slope of AB will be:

m= \frac{-1-1}{14-2}=-1/6

Using this slope and the point (2,1) we can write the equation for AB as:

y-1= \frac{-1}{6}(x-2) \\  \\ 
y= -\frac{1}{6}x+ \frac{1}{3}+1 \\  \\ 
y=-\frac{1}{6}x+ \frac{4}{3} 


The above equation is in slope intercept form. Thus the y-intercept of AB is 4/3.

Slope of AB is -1/6, so slope of BC would be 6. Using the slope 6 and coordinates of the point B, we can write the equation of BC as:

y - 1 = 6(x - 2)
y = 6x - 12 + 1
y = 6x - 11

Point C lies on the line  y = 6x - 11. So if the y-coordinate of C is 13, we can write:

13 = 6x - 11
24 = 6x
x = 4

The x-coordinate of point C will be 4.

Therefore, the answers in correct order are:

4/3 ,  6,  -11,  4
8 0
2 years ago
What is the average rate of change for this quadratic function for the interval from x = 0 to x = 2?
Mrrafil [7]
Answer is b hope this helps
8 0
2 years ago
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