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neonofarm [45]
2 years ago
14

Please help, i will mark you as brainliest​

Chemistry
2 answers:
olga nikolaevna [1]2 years ago
8 0
Hey , This photo is only a small part , you can find it on gg, search Reactivity Series , it will show all^^

Mrrafil [7]2 years ago
4 0

Answer:

The order of reactivity of metals is as follows, Potassium > Sodium > Lithium > Calcium > Magnesium > Aluminium > Zinc > Iron > Copper > Silver > Gold.

Explanation:

The reactivity of elements (metals) towards water decreases towards the right in a period. It also increases down the group. But zinc is more reactive towards water than iron. Hence the correct order is:

Iron<Zinc<Magnesium<Sodium

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To change an object from a liquid to a gas _________ must happen
nignag [31]
Evaporation!
-Melting is a solid to a liquid
-sublimation is directly from a solid to a gas
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4 0
3 years ago
Intermolecular Forces and Physical Properties of Pure Substances
sergiy2304 [10]

Answer: b

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5 0
3 years ago
For the following questions, name the ionic compound using a periodic table and the polyatomic ion chart. Be sure to use correct
Svet_ta [14]
Sodium Flouride
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I've answered another one of your questions with the content of how to work these out
6 0
3 years ago
Hey besties can y'all help me out
Lostsunrise [7]

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5 0
3 years ago
It take 38.70cm³ of 1.90m NaoH to neutralize 10.30cm³ of H2so4 in a battery, calculate the molar concentration of H2so4
zlopas [31]

Answer:

M_{acid}=3.57M

Explanation:

Hello there!

In this case, since this acid-base neutralization is performed in a 1:2 mole ratio of acid to base as the former is a diprotic acid (two hydrogen ions in the molecule), we can write the following equation:

2M_{acid}V_{acid}=M_{base}V_{base}

In such a way, we can solve for the molarity of the acid, given the molarity and concentration of the NaOH base and the volume of the acid:

M_{acid}=\frac{M_{base}V_{base}}{2V_{acid}}

Thus, we plug in the given data to obtain:

M_{acid}=\frac{38.70cm^3*1.90M}{2(10.30cm^3)} \\\\M_{acid}=3.57M

Best regards!

8 0
3 years ago
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