Answer:
The two types of collisions are :
Type a)
<u>Elastic collision</u>
Type b)
<u>Inelastic collision</u>
Explanation:
Collision : It is the event when two bodies collide with each other for small period of time.
During collision , the bodies exert force to each other.
Example :
When boxer hits with punches .
When bat hits the ball in cricket match.
So, collision is short duration interaction of two objects. When the objects collides , there is change in their velocity.
All collision follow law of conservation of momentum . Their type is decided by , whether they follow conservation of energy also.
<u>Compare and contrast the two types</u>
a) Elastic collision : Those collision in which no loss or gain of kinetic energy will occur. They follow conservation of kinetic energy. Example : ideal gaseous molecule
b) Inelastic collision : Those collision in which Change in kinetic energy will occur. They do not follow conservation of kinetic energy.Almost all conservation are inelastic.
Here Kinetic energy get converted into other form of energy.
Answer:
curium
−
243
,
252
/
99
Es,
251
/
98
Cf,
214
/
82
Pb
Explanation: Im not very good with this but here ya go!
Answer:
The Limiting Reactant is the reactant that when consumed the reaction stops.
Explanation:
Answer:
0.1082M of Barium Hydroxide
Explanation:
KHP reacts with Ba(OH)2 as follows:
2KHP + Ba(OH)2 → 2H2O + Ba²⁺ + 2K⁺ + 2P²⁻
<em>Where 2 moles of KHP reacts per mole of barium hydroxide</em>
<em />
To solve this question we must find the moles of KHP in 1.37g. With these moles and the reaction we can find the moles of Ba(OH)2 and its molarity using the volume of the solution (31.0mL = 0.0310L) as follows:
<em>Moles KHP -Molar mass: 204.22g/mol-</em>
1.37g * (1mol / 204.22g) = 0.006708 moles KHP
<em>Moles Ba(OH)2:</em>
0.006708 moles KHP * (1mol Ba(OH)2 / 2mol KHP) =
0.003354 moles Ba(OH)2
<em>Molarity:</em>
0.003354 moles Ba(OH)2 / 0.0310L =
<h3>0.1082M of Barium Hydroxide</h3>
