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mars1129 [50]
3 years ago
15

These steps are followed when using the half-life of carbon-14 to determine

Chemistry
2 answers:
Stella [2.4K]3 years ago
5 0

Answer: B.A.C

Explanation:

erastovalidia [21]3 years ago
4 0

Answer:

B. C, A, B

Explanation:

We can measure the age of an artifact by comparison of the activities a living sample with that of the artifact. This is so because the activity of the living sample represents the original activity of the artifact.

So, the steps involved in determining the age of an artifact is to measure the ratio of the parent and daughter nuclei. Then we use the half life of carbon to find out how many half lives have passed. Using this number of half lives that has passed, we can compute the age of the object.

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Scientific explanations
Sergio039 [100]

I think that it's cannot include supernatural explanations, or C.

If i got it wrong sorry  

6 0
3 years ago
A 0.1510 gram sample of a hydrocarbon produces 0.5008 gram CO2 and 0.1282 gram H2O in combustion analysis. Its
Over [174]
In a combustion of a hydrocarbon compound, 2 reactions are happening per element:

C + O₂ → CO₂
2 H + 1/2 O₂ → H₂O

Thus, we can determine the amount of C and H from the masses of CO₂ and H₂O produced, respectively.

1.) Compute for the amount of C in the compound. The data you need to know are the following:
Molar mass of C = 12 g/mol
Molar mass of CO₂ = 44 g/mol
Solution:
0.5008 g CO₂*(1 mol CO₂/ 44 g)*(1 mol C/1 mol CO₂) = 0.01138 mol C
0.01138 mol C*(12 g/mol) = 0.13658 g C

Compute for the amount of H in the compound. The data you need to know are the following:
Molar mass of H = 1 g/mol
Molar mass of H₂O = 18 g/mol
Solution:
0.1282 g H₂O*(1 mol H₂O/ 18 g)*(2 mol H/1 mol H₂O) = 0.014244 mol H
0.014244 mol H*(1 g/mol) = 0.014244 g H

The percent composition of pure hydrocarbon would be:
Percent composition = (Mass of C + Mass of H)/(Mass of sample) * 100
Percent composition = (0.13658 g + 0.014244 g)/(<span>0.1510 g) * 100
</span>Percent composition = 99.88%

2. The empirical formula is determined by finding the ratio of the elements. From #1, the amounts of moles is:

Amount of C = 0.01138 mol
Amount of H = 0.014244 mol

Divide the least number between the two to each of their individual amounts:
C = 0.01138/0.01138 = 1
H = 0.014244/0.01138 = 1.25

The ratio should be a whole number. So, you multiple 4 to each of the ratios:
C = 1*4 = 4
H = 1.25*4 = 5

Thus, the empirical formula of the hydrocarbon is C₄H₅.

3. The molar mass of the empirical formula is

Molar mass = 4(12 g/mol) + 5(1 g/mol) = 53 g/mol
Divide this from the given molecular weight of 106 g/mol
106 g/mol / 53 g/mol = 2
Thus, you need to multiply 2 to the subscripts of the empirical formula.

Molecular Formula = C₈H₁₀

4 0
3 years ago
Calculate the change in temperature (ΔT) that occurs when 8000 J of energy (q) is used to heat up a mass (m) of 75 g of water. (
pickupchik [31]

Answer:

The change in temperature that occurs when 8000 J of heat is used by a mass 75 g of water is 25.4 °C

Explanation:

H = mc ΔT

m = 75 g

c = 4. 200 J/ g °C

H = 8000 J

ΔT =?

Rearranging the formula, making ΔT the subject of formula;

ΔT = H / m c

ΔT = 8000 / 75 * 4.200

ΔT = 8000 / 315

ΔT = 25.4 °C

8 0
3 years ago
Read 2 more answers
5. __NH3 + __O2 &gt;&gt;&gt;&gt;&gt;__ NO +__ H20
inn [45]
2 NH3+ 2 O2 —> 2 NO+ 3 H2O
5 0
3 years ago
PLEASE HELP ME ASAPPP!?
Brrunno [24]

lets guess and say #4???

7 0
3 years ago
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