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2 years ago

These steps are followed when using the half-life of carbon-14 to determine

Chemistry

2 answers:

Stella [2.4K]2 years ago

5 0

Answer: B.A.C

Explanation:

erastovalidia [21]2 years ago

4 0

Answer:

B. C, A, B

Explanation:

We can measure the age of an artifact by comparison of the activities a living sample with that of the artifact. This is so because the activity of the living sample represents the original activity of the artifact.

So, the steps involved in determining the age of an artifact is to measure the ratio of the parent and daughter nuclei. Then we use the half life of carbon to find out how many half lives have passed. Using this number of half lives that has passed, we can compute the age of the object.

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dedylja [7]

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2 years ago

If there is no subscript to the right of a symbol means ________________ atom of that element?

julia-pushkina [17]

Explanation:

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3 years ago

A student mixed a small amount of iron filings and sulphur powder in a dish. He could not

Temka [501]

Answer:

$\huge \boxed{\mathrm{Carbon \ disulphide}}$

Explanation:

Carbon disulphide is the liquid that can be used to separate iron fillings and sulphur powder.

When carbon disulphide is poured into the dish, the sulphur powder gets easily dissolved in the carbon disulfide. The iron fillings are left to settle on the bottom of the dish.

The iron fillings can get seperated through filtration. When the mixture of sulphur powder and carbon disulphide gets completely evaporated, the sulphur powder is left over.

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2 years ago

A cube of an unknown metal measures 0.200 cm on one side. The mass of the cube is 52 mg. Which of the following is most likely t

Margarita [4]

Answer:

Option E. Zirconium

Explanation:

From the question given above, the following data were obtained:

Length of side (L) of cube = 0.2 cm

Mass (m) of cube = 52 mg

Name of the unknown metal =?

Next, we shall determine the volume of the cube. This can be obtained as follow:

Length of side (L) of cube = 0.2 cm

Volume (V) of the cube =?

V = L³

V = 0.2³

V = 0.008 cm³

Next, we shall convert 52 mg to g. This can be obtained as follow:

1000 mg = 1 g

Therefore,

52 mg = 52 mg × 1 g / 1000 mg

52 mg = 0.052 g

Thus, 52 mg is equivalent to 0.052 g.

Next, we shall determine the density of the unknown metal. This can be obtained as follow:

Mass = 0.052 g.

Volume = 0.008 cm³

Density =?

Density = mass / volume

Density = 0.052 / 0.008

Density of the unknown metal = 6.5 g/cm³

Comparing the density of the unknown metal i.e 6.5 g/cm³ with those given in table in the above, we can conclude that the unknown metal is zirconium

7 0

2 years ago

Why is it important to use chemicals of high quality (purity) and exact(correct) concentrations in experiments?

Darya [45]

It is important to use chemicals of high quality and correct concentrations in experiment so that we can obtain the predictable result in an experiment

Purity of substances/chemicals is very important when performing experiments in the laboratories, because it plays an important role in the determination of the chemical properties of substances which will have a direct effect on the result obtained from the experiment. likewise using the correct concentration of reagents

During experiments to obtain the best/predictable result in an experiment it is of best practice to make use of chemicals of high quality and also at the exact(needed) concentrations, that way the predictable result of the experiment will be obtained.

Learn more : brainly.com/question/8684258

6 0

2 years ago

Read 2 more answers