Answer:
x = -3
Explanation:
8(6x + 4) = -112
Divide both sides by 8.
6x + 4 = -14
Subtract 4 from both sides.
6x = -18
Divide both sides by 6.
x = -3
Answer:
HCl(aq) + KOH(aq) —> KCl(aq) + H2O(l)
Explanation:
Aqueous solution of HCl and aqueous solution of KOH react as follow:
HCl(aq) + KOH(aq) —>
In solution, HCl and KOH will dissociates as follow:
HCl —> H+ + Cl-
KOH —> K+ + OH-
During the reaction, a double displacement reaction occur as shown below:
H+ + Cl- + K+ + OH- —> K+Cl- + H+OH-
The elemental equation is given below:
HCl(aq) + KOH(aq) —> KCl(aq) + H2O(l)
I guess it is A and i think i m correct
Answer: The theoretical yield of potassium chloride is 0.596 grams and the % Yield of potassium chloride is 83.9%
Explanation:
To calculate the moles :
According to stoichiometry :
2 moles of
produce= 2 moles of
Thus 0.008 moles of
will produce=
of
Theoretical yield of
% yield = 
The theoretical yield of potassium chloride is 0.596 grams and the % Yield of potassium chloride is 83.9%
Theoretical yield is the amount supposedly produced by the reaction if it was complete. The balanced chemical reaction is:
Fe2O3(s) + 3 CO<span>(g) = 2 Fe(s) + 3 </span>CO<span>2(g)
</span>
We use the amounts given for the reactants as the starting point of the calculations. We do as follows:
13.4 g Fe2O3 ( 1 mol / <span>159.69 g ) = 0.08 mol
</span>12.3 g CO ( 1 mol / 28.01 ) = 0.44 mol
Therefore, the limiting reactant would be Fe2O3. We use this for the theoretical yield.
0.08 mol ( 2 mol Fe / 1 mol Fe2O3 ) = 0.16 mol Fe (THEORETICAL YIELD)
8.23 g ( 1 mol / 55.85 g ) = 0.15 mol Fe ( ACTUAL YIELD)
Percent yield = 0.15 / 0.16 x 100 = 93.75%