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finlep [7]
2 years ago
6

If one-trillionth of the atoms of a radioactive isotope disintegrate each day, what is the decay constant of the process?

Chemistry
1 answer:
Paul [167]2 years ago
3 0

Decay constant of the process 1×10^(-12) day^(-1).

<h3>What is decay constant?</h3>

A radioactive nuclide's probability of decay per unit time is known as its decay constant, which is expressed in units of s1 or a1. As a result, as shown by the equation dP/P dt =, the number of parent nuclides P declines with time t. Nuclear forces are about 1,000,000 times more powerful than electrical and molecular forces in their ability to bind protons and neutrons. The strength of the bonds holding the radioactive element are likewise indifferent to the decay probabilities and's, in addition to being unaffected by temperature and pressure. The decay constant is related to the nuclide's T 1/2 half-life by T 1/2 = ln 2/.

To know more about decay constant:

brainly.com/question/16623902

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