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topjm [15]
3 years ago
12

Read carefully and choose the correct answer.ill mark brainliest​

Chemistry
1 answer:
Veseljchak [2.6K]3 years ago
5 0

Answer:

Hello shaggy

Explanation:

Good morning dear

How are you

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What is the relationship between the moons surface gravity, lack of atmosphere, and temperature range?
luda_lava [24]
The main factor is the size of the moon. which is small compared to the earth, meaning that the moon has less gravity, and more gas is allowed to escape the surface, Which basically means theres no atmosphere.
8 0
3 years ago
You wish to make 250. mL of 0.20 M KCl from a stock solution of 1.5 M KCl and DI water.
Nitella [24]

The question requires us to use the dilution formula M_iV_i=M_fV_f, where M_i and V_i are the stock concentration and volume respectively, then M_f and V_f are the dilute concentration and volume respectively.

a. C_s_t_o_c_k= 1.5 M KCI, C_d_i_l_u_t_e=0.20M KCl, V_d_i_l_u_t_e=250ml KCl

b.M_iV_i=M_fV_f\\\implies V_i= \frac{M_fV_f}{M_i} = \frac{0.20M \times 250ml}{1.5M} = 33.3\ ml

To prepare the solution 33.3ml of 1.5M KCl is diluted to a total final volume of 250ml.


8 0
4 years ago
Complete the following paragraph.
gladu [14]

Explanation:

the stationary phase in TLC is a <u>silica gel coated metal plate or paper</u>.

The<u> individual</u> component of the mixure will travel a greater distance up the plate, resulting in a <u>Rf</u> value for the component.

the <u>p-Xylene  spot </u> will travel a greater distance as it is the <u>lighter</u> component

Bromobenzene will travel least as it is the <u>heavier</u> component.

thin layer chromatography (TLC) is a type of chromatographic seperation technique that is based on the molecular size of components. the Rf value is the distance covered by the component relative to that travelled by the solvent which is the mobile phase

3 0
3 years ago
The half-life of radium-226 is 1590 years. if a sample contains 100 mg, how many mg will remain after 1000 years?
AlladinOne [14]

Answer:

64.52 mg.

Explanation:

The following data were obtained from the question:

Half life (t½) = 1590 years

Initial amount (N₀) = 100 mg

Time (t) = 1000 years.

Final amount (N) =.?

Next, we shall determine the rate constant (K).

This is illustrated below:

Half life (t½) = 1590 years

Rate/decay constant (K) =?

K = 0.693 / t½

K = 0.693/1590

K = 4.36×10¯⁴ / year.

Finally, we shall determine the amount that will remain after 1000 years as follow:

Half life (t½) = 1590 years

Initial amount (N₀) = 100 mg

Time (t) = 1000 years.

Rate constant = 4.36×10¯⁴ / year.

Final amount (N) =.?

Log (N₀/N) = kt/2.3

Log (100/N) = 4.36×10¯⁴ × 1000/2.3

Log (100/N) = 0.436/2.3

Log (100/N) = 0.1896

Take the antilog

100/N = antilog (0.1896)

100/N = 1.55

Cross multiply

N x 1.55 = 100

Divide both side by 1.55

N = 100/1.55

N = 64.52 mg

Therefore, the amount that remained after 1000 years is 64.52 mg

7 0
4 years ago
What is the kinetic energy of a body with a mass of 0.500 kg that moves at a speed of 20.0 m/s?
Norma-Jean [14]

Answer:

100J = K.E

Explanation:

K.E =1/2 *m*v^2

= 1/2*0.500*(20.0)^2

= 1/2 *500/1000 *400

So here 2will cancel with 400,and it will be reduced to 200 then the zeros of 200 will cancel with 1000's zeroes and then when the zeros of 200 get cancelled with the zeroes of 1000 u will be left with 500/10 *2 then cancel 2 with 10 then u get 500/5 then reduce that u get 100.

Hope it helps pls mark as brainliest!!!

6 0
3 years ago
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