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just olya [345]
2 years ago
13

But-1-ene can be prepared from butan-1-ol. which type of reaction takes place?

Chemistry
1 answer:
slega [8]2 years ago
8 0

Answer:

              Dehydration Reaction

Explanation:

                  Alcohols can be converted into Alkenes using catalytic amounts of acids as a catalysts.

                 The water molecule is removed hence, it is called as dehydration reaction.

                  The reaction is attached.

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If eggs are so fragile, how do they actually protect the growing bird?​
Step2247 [10]

Although birds' eggs appear to be fragile, they are in fact extremely robust. The oval shape applies the same rules of engineering as an arched bridge; the convex surface can withstand considerable pressure without breaking.

6 0
3 years ago
A hot metal plate at 150°C has been placed in air at room temperature. Which event would most likely take place
arsen [322]

Answer:

All of the above

Explanation:

3 0
2 years ago
What was the resulting molarity of your primary standard solution of potassium iodate kio3?
melamori03 [73]
Missing question: 0,535 gram of KIO₃ dissolved in 250 mL of de-ionized water to <span>make primary standard solution.
m(</span>KIO₃) = 0,535 g.
V(KIO₃) = 250 mL ÷ 1000 mL/L = 0,25 L.
n(KIO₃) = m(KIO₃) ÷ M(KIO₃).
n(KIO₃) = 0,535 g ÷ 214 g/mol.
n(KIO₃) = 0,0025 mol.
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8 0
2 years ago
If you have 20.0 g of CO2, how many atoms of Oxygen (O) are present in the sample?
Alecsey [184]

Answer:

20 g of CO₂ have 5.47x10²³ oxygen atoms

Explanation:

1 mol of CO₂ has 1 mol of C and 2 moles of O.

Mass / Molar mass = Moles

20 g / 44 g/m = 0.454 moles

In 1 mol we find 2 moles of O

In 0.454 moles of CO₂, we will find ( 0.454  .2) = 0.909 moles

1 mol has _____ 6.02x10²³ atoms

0.909 moles have (0.909 .  6.02x10²³) = 5.47x10²³ atoms

7 0
2 years ago
Given: C + O2 → CO2 Bond Bond Energy (kJ/mol) C=O 799 O=O 494 Calculate the enthalpy change for the chemical reaction. The chang
aliya0001 [1]

Answer:

-1104 kJ/mol

Explanation:

The change in the enthalpy of a reaction is equal to the difference between: the sum of the enthalpy changes of the bonds broken and the sum of the enthalpy changes of the bonds formed.

The bonds broken correspond to the cleavage of bonds of the reactants, the bonds formed correspond to the bonds of the products:

  • we only break oxygen O=O bond, since carbon is not bonded to anything;
  • we form two C=O bonds in carbon dioxide.

Therefore, the enthalpy change is calculated by:

\Delta H^o = 1 mol\cdot 494 kJ/mol - 2 mol\cdot 799 kJ/mol = -1104 kJ/mol

3 0
2 years ago
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