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Vika [28.1K]
3 years ago
5

PLEASE HELP WITH EASY SCIENCE!

Chemistry
2 answers:
erastovalidia [21]3 years ago
5 0
The answer is B. dependent variable.
tiny-mole [99]3 years ago
4 0

Answer : Option B) Dependent variable.

Explanation : In this experiment the growth of pea plants is a dependent variable because, it depends upon the light which is available to it. As in the experiment James took two pea plants, and placed one in a dark closet and the other on a sunny window sill. Both were located in air-conditioned rooms. But the growth of the plant differs because of the light availability to it. Therefore, it is a dependent variable.

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The diagram shows a carrier wave before and after modulation. The diagram best represents which type of modulation? FM phase AM
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Calculate how many grams of the first reactant are necessary to completely react with 17.3 g of the second reactant. the reactio
soldier1979 [14.2K]

Taking into account the reaction stoichiometry, 16.611 grams of Na₂CO₃ are necessary to completely react with 17.3 g of CuCl₂.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

Na₂CO₃ + CuCl₂  → CuCO₃ + 2 NaCl

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Na₂CO₃: 1 mole
  • CuCl₂: 1 mole
  • CuCO₃: 1 mole
  • NaCl: 2 moles

The molar mass of the compounds is:

  • Na₂CO₃: 129 g/mole
  • CuCl₂: 134.45 g/mole
  • CuCO₃: 123.55 g/mole
  • NaCl: 58.45 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Na₂CO₃: 1 mole ×129 g/mole= 129 grams
  • CuCl₂: 1 mole ×134.45 g/mole= 134.45 grams
  • CuCO₃: 1 mole ×123.55 g/mole= 123.55 grams
  • NaCl: 2 mole ×58.45 g/mole=116.9 grams

<h3>Mass of CuCl₂ required</h3>

The following rule of three can be applied: If by reaction stoichiometry 134.35 grams of CuCl₂ react with 129 grams of Na₂CO₃, 17.3 grams of CuCl₂ react with how much mass of Na₂CO₃?

mass of Na₂CO₃= (17.3 grams of CuCl₂× 129 grams of Na₂CO₃)÷ 134.35 grams of CuCl₂

<u><em>mass of Na₂CO₃= 16.611 grams</em></u>

Finally, 16.611 grams of Na₂CO₃ is required.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

6 0
1 year ago
When 120 g of carbon reacts completely with 320 g of oxygen the mass of carbon dioxide formed will be?
olga2289 [7]
440 cause mass cant be created or destroyed
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