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kykrilka [37]
3 years ago
7

Which is the limiting reactant if we start with 30.0 g Al and 30.0 h O2​

Chemistry
1 answer:
lorasvet [3.4K]3 years ago
4 0

Al

Explanation:

The limiting reactant will be Al:

        4Al + 3O₂ → 2Al₂O₃

The limiting reactant is the reactant in short supply in a chemical reaction.

     Given parameters:

  Mass of Al = 30g  Molar mass = 27g/mol

         Number of moles = \frac{mass}{molar mass} =  \frac{30}{27}

         Number of moles of Al = 1.111 mole

  Mass of O₂ = 30g, molar mass = 32g/mol

   Number of moles =  \frac{30}{32} = 0.94mol

In the reaction:

          4 moles of Al reacted with 3 moles of O₂

         1.11moles of Al will require \frac{1.11 x3}{4} = 0.83mole to react

But we have been given 0.94mole of O₂. This is more than required.

Therefore O₂ is in excess and Al is the limiting reactant.

Learn more:

Limiting reagents brainly.com/question/6078553

#learnwithBrainly

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Write the fraction of the mass of kcl produced from 1 g of k2c03​
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<h3>Further explanation</h3>

Given

1 g of K₂CO₃

Required

Mass of KCl

Solution

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