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3 years ago

How could you tell whether a liquid is honey or vinegar?

2 answers:

4 0

Based on the liquids viscosity (which is a measure of how quickly/slowly a fluid can flow).

Higher viscosity represents a "thicker" liquid & slower flow (honey)
Lower viscosity represents a "thinner" liquid & quicker flow (vinegar)

Julli [10]3 years ago

3 0

I really don't recommend identifying substances by taste, but honey is sweet,

while vinegar is sour. A safer way would be to see if one is more viscous

than the other. Viscosity is the ability to pour a fluid. This is a topic in fluid

dynamics. Hydrodynamics and aerodynamics are sub-specialties.

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Calculate the density of an object with a mass of 30g and volume of 6cm^3

Kipish [7]

Density = Mass ÷ Volume

D= 30g ÷ 6 cm^3

D= 5 g/dm^3

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2 years ago

How will adding NaCl affect the freezing point of a solution?

lord [1]

Answer is: adding NaCl will lower the freezing point of a solution.

A solution (in this example solution of sodium chloride) freezes at a lower temperature than does the pure solvent (deionized water).

The higher the solute concentration (sodium chloride), freezing point depression of the solution will be greater.

Equation describing the change in freezing point:

ΔT = Kf · b · i.

ΔT - temperature change from pure solvent to solution.

Kf - the molal freezing point depression constant.

b - molality (moles of solute per kilogram of solvent).

i - Van’t Hoff Factor.

Dissociation of sodium chloride in water: NaCl(aq) → Na⁺(aq) + Cl⁻(aq).

3 0

2 years ago

Read 2 more answers

The solubility of o2 at 20c is 1.38 x10^-3. the partial presure of o2 in the air at sea level is 0.27 atm. using henery;s law, c

netineya [11]

<u>Answer:</u> The solubility of oxygen at 682 torr is $4.58\times 10^{-3}M$

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{A}=K_H\times p_{A}$

Or,

$\frac{C_{1}}{C_{2}}=\frac{p_{1}}{p_2}$

where,

$C_1\text{ and }p_1$ are the initial concentration and partial pressure of oxygen gas

$C_2\text{ and }p_2$ are the final concentration and partial pressure of oxygen gas

We are given:

Conversion factor used: 1 atm = 760 torr

$C_1=1.38\times 10^{-3}M\\p_1=0.27atm\\C_2=?\\p_2=682torr=0.897atm$

Putting values in above equation, we get:

$\frac{1.38\times 10^{-3}}{C_2}=\frac{0.27atm}{0.897atm}\\\\C_2=\frac{1.38\times 10^{-3}\times 0.897atm}{0.27atm}=4.58\times 10^{-3}M$

Hence, the solubility of oxygen gas at 628 torr is $4.58\times 10^{-3}M$

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2 years ago

Scientists group similar organisms together through a process called …..

Bond [772]

Answer:

plz i need to ask another question i hope u understand

Explanation:

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3 years ago

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A gold nugget has a volume of 20.0 cm3 and its density is 19.3 g/cm3. What is the mass of the gold nugget?

salantis [7]

Density * Volume = Mass

Now we substitute the values in.

19.3 g/cm^3 + 20 cm^3 = 386 g

Mass = 386 g

5 0

3 years ago

Read 2 more answers