Question

Dawn is making an abstract painting with two triangles. The dimensions of the painting are shown below: Two triangles share the same height of 8 inches. One triangle has a base of 8 inches and the other is 6 inches. The total area of the two triangles is _____ square inches. Numerical Answers Expected! Answer for Blank:

Answer 1

Answer:

The total area of the two triangles is 56 inches²

Explanation:

                      $\boxed{Area - of -triangle: \frac{1}{2} * base * height }$

Here given that the height for both triangles is same: 8 inches and bases differ by each: 8 inches and 6 inches.

using the formula:

area of both triangles:

$\boxed{\frac{1}{2} * 8 * 8 + \frac{1}{2} * 6 * 8}$

$\boxed{32 + 24}$

$\boxed{56}$

Answer 2

Area of triangle : $\frac{1}{2} \times base \times height$

Here given that the height for both triangles is same: $8$ inches and bases differ by each: $8$ inches and $6$ inches.

Using the formula:

Area of both triangles:

$→ \frac{1}{2} \times 8 \times 8 + \frac{1}{2} \times 6 \times 8$

$→32 + 24$

$→56$

Answer :— $56 \: inches ^{2}$