All categories

2 years ago

When using microscopes, what are the two variables that matter the mosti think its chemistry.

Chemistry

1 answer:

PtichkaEL [24]2 years ago

4 0

Answer:

magnification and resolution

Explanation:

Two parameters are especially important in microscopy: magnification and resolution. Magnification is a measure of how much larger a microscope (or set of lenses within a microscope) causes an object to appear.

You might be interested in

How does e=mc^2 connect to quarks

Jobisdone [24]

Answer:

good bro

Explanation:

5 0

3 years ago

Suppose your teacher ask you to separate a mixture of sand and water.Which of the following merhods would u use:distillation fil

MrRa [10]

Answer:

Filtration

Explanation:

Filtration would be best because the sand particles would be trapped in the filter paper and the water would go through so the mixture would be separated

7 0

3 years ago

A student is trying to calculate the density of an ice cream cone. She already knows the mass, but she needs to determine the vo

IgorLugansk [536]

<span>V equals one-third times pi times r squared times h</span>

6 0

3 years ago

Read 2 more answers

). The molar mass of an organic acid, a compound composed of carbon, hydrogen, and oxygen, is 194.14 g/mol. Combustion of a 1.50

Nikitich [7]

Answer:

The empirical formula is C₆H₁₀O₇.

Step-by-step explanation:

1. Calculate the masses of C, H, and O from the masses given.

Mass of C = 2.0402 g CO₂ × (12.01 g C/44.01 g CO₂) = 0.5568 g C

Mass of H = 0.6955 g H₂O × (2.016 H/18.02 g H₂O) = 0.077 81 g H

Mass of O = Mass of compound - Mass of C - Mass of H = (1.500 – 0.5568 – 0.077 81) g = 0.8654 g O

=====

2. Convert these masses to moles.

Moles C = 0.5568 × 1/12.01 = 0.046 36

Moles H = 0.077 81 × 1/1.008 = 0.077 19

Moles O = 0.8654 × 1/16.00 = 0.054 09

=====

3. Find the molar ratios.

Moles C = 0.046 36/0.046 36 = 1

Moles H = 0.077 19/0.046 36 = 1.665

Moles O = 0.054 09/0.046 36 = 1.167

======

4. Multiply the ratios by a number to make them close to integers

C = 1 × 6 = 6

H = 1.665 × 6 = 9.991

O = 1.167 × 6 = 7.001

=====

5. Round the ratios to integers

C:H:O =6:10:7

=====

6. Write the empirical formula

The empirical formula is C₆H₁₀O₇.

=======

7. Calculate the empirical formula mass

C₆H₁₀O₇ = 6×12.01 + 10×1.008 + 7×16.00

C₆H₁₀O₇ = 72.01 + 10.08+ 112.0

C₆H₁₀O₇ = 194.09

=====

8. Divide the molecular mass by the empirical formula mass.

MM/EFM = 194.14/194.09 = 1.000 ≈ 1

=====

9. Determine the molecular formula

MF = (EF)ₙ = (C₆H₁₀O₇)₁ = C₆H₁₀O₇

7 0

3 years ago

For the following species, draw a Lewis structure for one important resonance form. Include all lone pair electrons and assign f

Gemiola [76]

Answer:

The Lewis structures are shown in the figure

Explanation:

The lewis structure will be drawn using following steps

i) we will calculate the total number of valence electrons in the molecule

ii) will assign one bond (two electrons in between two atoms)

iii) then distribute the rest of the valence electrons as lone pair or shared pair based on completion of octet.

The structure of each molecule is given in the figure.

Valence electrons:

$NO_{2}^{+}$

V.E = 5 +(2)6-1=16

$NO_{2}F$

V.E =5 +(2)6+7=24

6 0

3 years ago

When using microscopes, what are the two variables that matter the mosti think its chemistry.​

When using microscopes, what are the two variables that matter the mosti think its chemistry.