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Elenna [48]
2 years ago
11

When using microscopes, what are the two variables that matter the mosti think its chemistry.​

Chemistry
1 answer:
PtichkaEL [24]2 years ago
4 0

Answer:

magnification and resolution  

Explanation:

Two parameters are especially important in microscopy: magnification and resolution. Magnification is a measure of how much larger a microscope (or set of lenses within a microscope) causes an object to appear.

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Which option is a valid hypothesis in the correct format?
Rashid [163]

Answer:

4. If cotton plants need a consistent amount of water to grow steadily, then a cotton plant that displays steady growth will receieve 100 mL of water every day.

Explanation:

Hypotheses are written in the format of "If... then...". It should include information on both variables to arrive at a conclusion point.

5 0
3 years ago
Using the following equation: 3H2SO4+ 2Fe -> Fe2(SO4)3+ 3H2
Mariana [72]

Answer:

H₂SO₄

Explanation:

Given data:

Number of moles of H₂SO₄ = 15 mol

Number of moles of Fe = 13 mol

Which reactant is limiting reactant = ?

Solution:

Chemical equation:

3H₂SO₄  + 2Fe      →          Fe₂(SO₄)₃  + 3H₂

now we will compare the moles reactant with product.

               H₂SO₄         :          Fe₂(SO₄)₃  

                  3               :              1

                 15               :              1/3×15 = 5

                H₂SO₄         :            H₂

                  3               :              3

                 15               :              15

                Fe               :          Fe₂(SO₄)₃  

                  2               :              1

                 13               :              1/2×13 = 6.5

                Fe               :                H₂

                  2               :                 3

                 13               :              3/2×13 = 19.5

Number of moles of product formed by  H₂SO₄ are less thus it will act as limiting reactant.

8 0
3 years ago
Methanol (CH3OH) has a heat of fusion of 3.16 kJ/mol. Which of the following is the heat of solidification that occurs when 64 g
Alexandra [31]
To determine the heat dissipated when a substance freezes, we multiply the heat of fusion of the substance to the mass of the substance that freezes. We calculate as follows:

Heat = -3.16 (64/32.06) = - 6.32 kJ

Hope this answers the question.
5 0
3 years ago
Read 2 more answers
Which is not a reason why mass of an atom is expressed in atomic mass units rather than in grams?
Tasya [4]
What are your answer choices? Scientists express the weight in AMU’s so that they can easily think about the weight of the atom. If it is expressed in grams, they’re constantly dealing with a weight that’s around 10^-24 grams, which is hard to deal with.
8 0
3 years ago
H2O and C6H12O6 are examples of ______
ruslelena [56]

Compounds. They both have more than one element in them

4 0
3 years ago
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