The metal ball lost energy while the putty ball gained energy.
<h3>What is momentum?</h3>
Momentum is the product of mass and velocity of the body. We must note that momentum before collision is equal to momentum after collision.
1) Kinetic energy before collision = 1/2mv^2 = 0.5 * 6 * 4 = 12 J
2) kinetic energy after collision = 0.5 * 6 * 2= 6 J
3) Kinetic energy of putty ball = 0.5 * 6 * 2= 6 J
4) Energy lost by the metal ball = 12 J - 6 J = 6 J
5) Energy gained by the putty ball = 6 J - 0J = 6 J
6) The rest of the energy was converted to heat after the collision.
Learn more about kinetic energy: brainly.com/question/999862
Answer:

Generally given that the electric field is negative it mean that its direction is opposite to that of the force
Explanation:
From the question we are told that
The charge on the small object is 
The force is 
Generally the magnitude of the electric field is mathematically represented as

=> 
=> 
Generally given that the electric field is negative it mean that its direction is opposite to that of the force
<h2>Answer:</h2>
<u>Ball A has more kinetic energy</u>
<h2>Explanation:</h2>
As we know that Kinetic energy is given by
K. E = 1/2 mv²
Since K E is dependent upon both mass and velocity so increasing mass will produce more kinetic energy if the speed remains constant
As the mass of ball A is greater than ball B so we can say that the kinetic energy of ball is more than ball B
Answer:
1.44 x 10⁻⁶ C
Explanation:
= charge on one sphere
= charge on other sphere
= Total charge on the two spheres = 40 μC
=
= 40 x 10⁻⁶
= (40 x 10⁻⁶) -
eq-1
= distance between the two spheres = 50 cm = 0.50 m
= magnitude of force between the two spheres = 2.0 N
Magnitude of force between the two spheres is given as


= 1.44 x 10⁻⁶ C
Hi, thank you for posting your question here at Brainly.
Newton's second law of motion can be expressed as Fnet = ma. The next external for acting on, say for example, a moving car are the following:
*weight due to gravity (force down)
*friction force between he road and the car's tires (force opposite the car's direction)