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3 years ago

Someone help me please!!

Physics

2 answers:

patriot [66]3 years ago

7 0

Pretty sure it's C) condensation because all of the others required heat to be added

Nastasia [14]3 years ago

6 0

All of them require an input of energy as they all need the energy to function. It may be changing the Temperature though if it is referring to natural changes as their is no need energy change

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If a neutral material like fur is rubbed on another neutral object like a rubber ball what is the resulting charges of the objec

alexdok [17]

Answer:

Explanation:

they both have a neutral charge so they couldn't be positive or negative since that wouldn't come from anywhere

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3 years ago

A 20000 kg railroad car is rolling at 1.00 m/s when a 1000 kg load of gravel is suddenly dropped in. part a what is the car's sp

Talja [164]

Using conservation of energy and momentum we get m1*v1=(m1+m2)*v2 so rearranging for v2 and plugging the given values in we get:
(200000kg*1.00m/s)/(21000kg)=.952m/s

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3 years ago

To calibrate the calorimeter electrically, a constant voltage of 3.6 V is applied and a current of 2.6 A flows for a period of 3

hodyreva [135]

Answer : The correct option is, (c) $3.7\times 10^2J/^oC$

Explanation :

First we have to calculate the energy or heat.

Formula used :

$E=V\times I\times t$

where,

E = energy (in joules)

V = voltage (in volt)

I = current (in ampere)

t = time (in seconds)

Now put all the given values in the above formula, we get:

$E=(3.6V)\times (2.6A)\times (350s)$

$E=3276J$

Now we have to calculate the heat capacity of the calorimeter.

Formula used :

$C=\frac{E}{\Delta T}=\frac{E}{T_{final}-T_{initial}}$

where,

C = heat capacity of the calorimeter

$T_{initial}$ = initial temperature = $20.3^oC$

$T_{final}$ = final temperature = $29.1^oC$

Now put all the given values in this formula, we get:

$C=\frac{3276J}{(29.1-20.3)^oC}$

$C=372.27J/^oC=3.7\times 10^2J/^oC$

Therefore, the heat capacity of the calorimeter is, $3.7\times 10^2J/^oC$

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3 years ago

X + 10 times X = 50 what is the answer

tia_tia [17]

Answer:

4.54

Explanation:

X+10X=50

11X=50

X=4.54#

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3 years ago

The normal boiling point of cyclohexane is 81.0 ℃. what is the vapor pressure of cyclohexane at 81.0 ℃?

Hitman42 [59]

The boiling point is defined as the temperature at which the pressure of the vapor of the liquid is equivalent to the external atmospheric pressure surrounding the liquid. Therefore, the boiling point of the liquid is dependent on the atmospheric pressure.

Based on this, the vapor pressure of cyclohexane at 81 degrees celcius will be equal to atmospheric pressure (based on barometric readings)<span />

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3 years ago