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snow_tiger [21]
3 years ago
11

Someone help me please!!

Physics
2 answers:
patriot [66]3 years ago
7 0
Pretty sure it's C) condensation because all of the others required heat to be added
Nastasia [14]3 years ago
6 0
All of them require an input of energy as they all need the energy to function. It may be changing the Temperature though if it is referring to natural changes as their is no need energy change 

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4 0
3 years ago
Around which months does el nino end and la nina start?
ad-work [718]

Answer:

They both tend to develop during the spring (March-June), reach peak intensity during the late autumn or winter (November-February), and then weaken during the spring or early summer (March-June)

3 0
3 years ago
Read 2 more answers
The current theory of the structure of the
Elza [17]

Answer:  91.4 J

Explanation:

Kinetic energy is the energy possessed by a body due to virtue of its motion.

K.E. = 0.5 m v²

Mass of the continent is given, m = 1.819 × 10²¹ kg

Side of the block of continent, s = 4150 km = 4150000 m

Depth of the block of continent, d = 38 km = 38000 m

(Mass = density × volume

m = 2780 kg/m³× (4150 × 10³ m)²× 38 × 10³ m = 1.819 × 10²¹ kg)

The continent is moving at the rate of, v = 1 cm /year = 0.01 m / 31556926 s = 3.17 × 10⁻¹⁰ m/s

⇒ K.E. = 0.5 × 1.819 × 10²¹ kg × (3.17 × 10⁻¹⁰ m/s)²= 91.4 J

Hence, mass of the continent has 91.4 J of kinetic energy.

5 0
3 years ago
Automobile traveling at 65 mph constant on the road described below. Find rate at which radar must rotate when theta = 15 deg. A
Finger [1]

Answer:

The rate at which radar must rotate is 0.335 rad/s.

Explanation:

Given that,

Velocity = 65 m/h = 29.0576 m/s

Angle = 15°

Suppose, the radius given by

r=(100\cos2\theta)\ m

We need to calculate the rate at which radar must rotate

Using formula of linear velocity

v=r\omega

\omega=\dfrac{v}{r}

Where, v = velocity

r = radius

Put the value into the formula

\omega=\dfrac{29.0576}{100\cos30}

\omega=0.335\ rad/s

Hence, The rate at which radar must rotate is 0.335 rad/s.

3 0
3 years ago
An object is made up of three masses connected by massless rods of fixed length. Mass A is located at (30.0 cm, 0 cm) and has a
puteri [66]

Answer:

0.0605 Kg m^2

Explanation:

In this case where we have find he moment of inertia of this object about an axis perpendicular to the x-y plane and passing through the origin,  we can just add three moment of inertia's .

MOI= 0.25×0.3^2 + 0.35×0.4^2- 0.45×0.2^2

= 0.0605 Kg m^2

8 0
4 years ago
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