Answer:
The mass of the ball is 0.23 kg
Explanation:
Given that
radius ,r= 3.74 cm
Density of the milk ,ρ = 1.04 g/cm³ = 1.04 x 10⁻³ kg/cm³
Normal force ,N= 9.03 x 10⁻² N
The volume of the ball V
V= 219.13 cm³
The bouncy force on the ball = Fb
Fb = ρ V g
Fb + N = m g
m=Mass of the ball = Density x volume
m = γ V , γ =Density of the Ball
ρ V g + N = γ V g ( take g= 10 m/s²)
γ = 0.00108 kg/cm³
m = γ V
m = 0.00108 x 219.13
m= 0.23 kg
The mass of the ball is 0.23 kg
Answer:
Ek1 = 900000 [J]
Ek1 = 400000 [J]
Explanation:
In order to solve this problem we must remember that kinetic energy is defined as the product of mass by velocity squared by a medium. Therefore using the following equation we have:
where:
m = mass = 500 [kg]
v1 = 60 [m/s]
So we have:
Ek1 = 0.5*500*(60^2)
Ek1 = 900000 [J]
and:
Ek2 = 0.5*500*(40^2)
Ek2 = 400000 [J]
the answer is C. It allows citizens to submit anonymous tips to the police.
Answer:The place to go for the answer to such an easy question is the SI Brochure, the document which defines the SI and all its units.
Answer:
Explanation:
cSep 20, 2010
well, since player b is obviously inadequate at athletics, it shows that player b is a woman, and because of this, she would not be able to hit the ball. The magnitude of the initial velocity would therefore be zero.
Anonymous
Sep 20, 2010
First you need to solve for time by using
d=(1/2)(a)(t^2)+(vi)t
1m=(1/2)(9.8)t^2 vertical initial velocity is 0m/s
t=.45 sec
Then you find the horizontal distance traveled by using
v=d/t
1.3m/s=d/.54sec
d=.585m
Then you need to find the time of player B by using
d=(1/2)(a)(t^2)+(vi)t
1.8m=(1/2)(9.8)(t^2) vertical initial velocity is 0
t=.61 sec
Finally to find player Bs initial horizontal velocity you use the horizontal equation
v=d/t
v=.585m/.61 sec
so v=.959m/s
