In a sound wave, the wavelength is equivalent to the distance from a region of high pressure to the region of mean

A project for a science class asks teams of students to build a windmill. The windmill is placed in front of a large floor fan.

shtirl [24]

The answer to your question would be team C, because the lifted the most weight in the shortest time. Team A might have been the fastest team but the also lifted the least amount of weight. And team B lifted a good amount of weight but they also did it the slowest.

8 0

3 years ago

With the piston head locked in place, will the volume of the gas increase, decrease, or stay the same whenthe piston is placed a

Nuetrik [128]

Answer:

For real gas the volume of a given mass of gas will increase with increase in temperature.

Explanation:

With the piston head locked in place and place above the fire,the volume of the gas will increase,because the volume of a given mass of gas increases with increase temperature.

6 0

3 years ago

A steel ball rolls with a constant velocity on a tabletop 0.950 m high it rolls off and hit the ground 0.352 m from the edge of

sp2606 [1]

Answer:

0.799 m/s if air resistance is negligible.

Explanation:

For how long is the ball in the air?

Acceleration is constant. The change in the ball's height $\Delta h$ depends on the square of the time:

$\displaystyle \Delta h = \frac{1}{2} \;g\cdot t^{2} + v_0\cdot t$ ,

where

$\Delta h$ is the change in the ball's height.
$g$ is the acceleration due to gravity.
$t$ is the time for which the ball is in the air.
$v_0$ is the initial vertical velocity of the ball.

The height of the ball decreases, so this value should be the opposite of the height of the table relative to the ground. $\Delta h = -0.950\;\text{m}$ .
Gravity pulls objects toward the earth, so $g$ is also negative. $g \approx -9.81\;\text{m}\cdot\text{s}^{-2}$ near the surface of the earth.
Assume that the table is flat. The vertical velocity of the ball will be zero until it falls off the edge. As a result, $v_0 = 0$ .

Solve for $t$ .

$\displaystyle \Delta h = \frac{1}{2} \;g\cdot t^{2} + v_0\cdot t$ ;

$\displaystyle -0.950 = \frac{1}{2} \times (-9.81) \cdot t^{2}$ ;

$\displaystyle t^{2} =\frac{-0.950}{1/2 \times (-9.81)}$ ;

$t \approx 0.440315\;\text{s}$ .

What's the initial horizontal velocity of the ball?

Horizontal displacement of the ball: $\Delta x = 0.352\;\text{m}$ ;
Time taken: $\Delta t = 0.440315\;\text{s}$

Assume that air resistance is negligible. Only gravity is acting on the ball when it falls from the tabletop. The horizontal velocity of the ball will not change while the ball is in the air. In other words, the ball will move away from the table at the same speed at which it rolls towards the edge.

$\begin{aligned}\text{Rolling Velocity}&=\text{Horizontal Velocity} \\&= \text{Average Horizontal Velocity}\\ &=\frac{\Delta x}{\Delta t}=\frac{0.352\;\text{m}}{0.440315\;\text{s}}=0.0799\;\text{m}\cdot\text{s}^{-1}\end{aligned}$ .

Both values from the question come with 3 significant figures. Keep more significant figures than that during the calculation and round the final result to the same number of significant figures.

3 0

3 years ago

The distance traveled, in feet, of a ball dropped from a tall building is modeled by the equation d(t) = 16t2 where d equals the

Ainat [17]

When t=2, the ball has fallen   d(2) = 16 (2²) = 64 feet .

When t=5, the ball has fallen   d(5) = 16 (5²) = 400 feet .

Distance fallen from t=2 until t=5 is (400 - 64) = 336 feet.

Time period between t=2 until t=5 is (5 - 2) = 3 seconds.

Average speed of the ball from t=2 until t=5 is

   (distance covered) / (time to cover the distance)

   =    336 feet    /    3 seconds = 112 feet per second.

That's what choice-C says.

6 0

3 years ago

Hello, I want to ask. . anyone knows the answer.

stealth61 [152]

I would say D. because you round to the nearest whole number and 0.04 is way less than 0.5 which is a good rounding up number.

5 0

3 years ago