Answer:
v = 8.89 cm/s
Explanation:
given,
frequency of ultrasonic wave = 2.23 x 10⁶ Hz
beat frequency = 258 Hz
speed of sound in the tissue = 1.54×10³ m/s
maximum velocity = ?
using Doppler equation
..........(1)
..........(2)
now, from equation (1) and (2)
f₂ = 2.23 x 10⁶ + 258 = 2230258 Hz
f₀ = 2.23 x 10⁶ Hz
c = 1540 m/s
1.00012(1540 - v ) = 1540+ v
1540.178 - 1.00012 v = 1540 + v
2.00012 v = 0.178
v = 0.08899 m/s
v = 8.89 cm/s
A electron has a negative charge. They represent energy levels.
An example of the use of an electron is the spherical shell. The larger the shell, the more energy the electron has.
Answer:
a)v = 476.28 m / s
, b) T = 6.69 10⁵ N
, c) λ = 0.486 m
, d) λ = 0.35 m
Explanation:
a) The speed of a wave on a string is
v = √T /μ
also all the waves fulfill the relationship
v = λ f
they indicate that the fundamental frequency is f = 980 Hz.
The wavelength that is fixed at its ends and has a maximum in the center
L = λ / 2
λ = 2L
we substitute
v = 2 L f
let's calculate
v = 2 0.243 980
v = 476.28 m / s
b) The tension of the rope
T = v² μ
the density of the string is
μ = m / L
T = v² m / L
T = 476.28² 0.717 / 0.243
T = 6.69 10⁵ N
c) λ = 2L
λ = 2 0.243
λ = 0.486 m
d) The violin has a resonance process with the air therefore the frequency of the wave in the air is the same as the wave in the string. Let's find the wavelength in the air
v = λ f
λ= v / f
λ = 343/980
λ = 0.35 m
Answer:
Magnetic Forces on Moving Charges. The magnetic force on a free moving charge is perpendicular to both the velocity of the charge and the magnetic field with direction given by the right hand rule.
Answer:
Diameter of a sphere: d = 2 * r , Surface area of a sphere: A = 4 * π * r² , Volume of a sphere: V = 4/3 * π * r³ , Surface to volume ratio of a sphere: A / V = 3 / r . To Measure Diameter of a Small Spherical/ Cylindrical Body Using Vernier's Callipers.
Explanation:
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