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Whitepunk [10]
3 years ago
8

A 1.0 kg rock moving at 8.4 m/s will have ______ of kinetic energy

Physics
1 answer:
BlackZzzverrR [31]3 years ago
4 0
K.E=1/2mv^2 K.E=1/2multiply1multiply8^2=32joules
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ndicate whether the statement is true or false. Whenever we move, we alter the rate at which we move into the future. A. True B.
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Whenever we move, we alter the rate at which we move into the future. This statement is true. 
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2 years ago
Both lead and zinc are formed as precipitates. Which of these is a step in the formation of the minerals?
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Minerals are naturally occurring inorganic (they're not formed from amino acids, peptides, or enzymes) chemical compounds.

From the given options, the following describes a step in the formation of the minerals: materials break up due to rise in temperature.

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3 years ago
Suppose you designed a spacecraft to work by photon pressure. The sail was a completely absorbing fabric of area 1.0 km2 and you
Alekssandra [29.7K]

Answer:

(a) F = 6.14 *10⁻⁴ N

(b) P = 6.14* 10⁻¹⁰ Pa

(c) t = 27.2 min

Explanation:

Area of sail A = 1.0 km² = 1.0 * 10⁶m²

Wavelength of light  λ = 650 nm = 650 * 10⁻⁹ m

Rate of impact of photons R = 1 mol/s = 6.022 * 10²³ photons/s

(a)

Momentum of each photon is Ρ = h/λ = 6.625 * 10⁻³⁴ / 650 * 10⁻⁹

      = 1.0192 * 10⁻²⁷ kg.m/s

Since the photons are absorbed completely, in every collision the above momentum is transferred to the sail.  

Momentum transferred to the sail per second is product of rate of impact of photons and momentum transferred by each photon.

dp/dt = R * h/ λ

This is the force acting on the sail.

F = R * h/λ = 6.022 * 10²³ * 1.0192 * 10⁻²⁷ = 6.14 *10⁻⁴ N

F = 6.14 *10⁻⁴ N

b)

Pressure exerted by the radiation on the sail = Force acting on the sail / Area of the sail

P = F/A =  6.14 * 10⁻⁴ / 1.0 * 10⁶ =  6.14* 10⁻¹⁰ Pa

P = 6.14* 10⁻¹⁰ Pa

c)  

Acceleration of spacecraft a = F/m = 6.14 * 10⁻⁴ /1.0 = 6.14 * 10⁻⁴m/s²

As the spacecraft starts from rest, initial speed u=0,m/s ,

final speed is u = 1.0 m/s after time t  

v = u+at  

t = 1.0 - 0/ 6.14 * 10⁻⁴ =  1629s = 27.2 min

t = 27.2 min

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3 years ago
Ocean currents near the equator are primarily: eastward westward north and south clockwise
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While running around the track at school, Milt notices that he runs due East in the 100m homestretch and due West on the 100m ba
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They have equal magnitudes and opposite directions.

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