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dimaraw [331]
3 years ago
6

Two gases X and Y are found in the atmosphere in only trace amounts because they decompose quickly. When exposed to ultraviolet

light the half-life of X is 1.25 h, while that of Y is 150 min.
Suppose an atmospheric scientist studying these decompositions fills a transparent 20.0 L flask with X and Y and exposes the flask to UV light. Initially, the partial pressure of X is 25.0% greater than the partial pressure of Y.
1. Will the partial pressure of X ever fall below the partial pressure of Y? (yes or no)
2. If yes, calculate the time it take the partial pressure of X to fall below the partial pressure of Y.
Chemistry
1 answer:
igomit [66]3 years ago
5 0

Answer:

1. Yes

2. After 68.1 mins, pX < pY.

Explanation:

Assuming the total gas pressure is 1 atm, let the partial pressure of Y be y, partial pressure of X will be 0.25y + y = 1.25y

1.25y + y = 1atm

2.25y = 1 atm

y = 1 atm / 2.25 = 0.44 atm

Then partial pressure of X = 0.56 atm

The partial pressure of a gas in a mixture of gases is directly proportional to the mole fraction of the gas.

Therefore the mole fraction of X and Y is 0.56 and 0.44 respectively.

The partial pressures of X and Y becomes half of their original values at 1.25 h = 85 min and Y at 150 min respectively.

The partial pressure after some time can be calculated from the half-life equation :

m = m⁰ *  1/2ⁿ

Where m = the remaining mass, m⁰ = initial mass, and n is number of half-lives undergone.

Let partial pressures represent the mass, and n for X and Y be a and b respectively:

pX  = 0.56/2ᵃ

pY = 0.44/2ᵇ

We then determine when Partial pressure of X, pX = Partial pressure of Y, pY

0.56/2ᵃ = 0.44/2ᵇ

2ᵃ/2ᵇ = 0.56/0.44

2ᵃ/2ᵇ = 1.27

2ᵃ⁻ᵇ = 2⁰°³⁴⁵

a - b = 0.345

Let this time be t, therefore,

For X; t = 85a and For Y: t = 150b

85a = 150b

then, a = 1.76b

1.76b - b = 0.345

0.760b = 0.345

b = 0.454 and,

a = 0.345 + 0.454 = 0.799

So,  X goes through 0.779 half-lives while Y goes through 0.454 half-lives Then, the time for both X and Y to have the same amount is:

t = 150 * 0.454 = 68.1 min

After 68.1 mins, pX < pY.

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What is the pressure, in atm, exerted by 41.6 g oxygen in a 22.0L container at 30.0C ?
Reika [66]

Answer:

1.47 atm

Explanation:

Step 1: Calculate the moles corresponding to 41.6 g of oxygen

The molar mass of oxygen is 32.00 g/mol.

41.6 g × 1 mol/32.00 g = 1.30 mol

Step 2: Convert 30.0 °C to Kelvin

We will use the following expression.

K = °C + 273.15 = 30.0 + 273.15 = 303.2 K

Step 3: Calculate the pressure exerted by the oxygen

We will use the ideal gas equation.

P × V = n × R × T

P = n × R × T / V

P = 1.30 mol × (0.0821 atm.L/mol.L) × 303.2 K / 22.0 L = 1.47 atm

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lesantik [10]
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(3 Points)
prisoha [69]
Your answer is B. radio waves have shorter wavelenghts than microwaves.
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5 0
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Read 2 more answers
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scZoUnD [109]

#6).
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You have to know that both sides of a rectangle are the same length,
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#8).
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#10).
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The problem wants to know how many kilometers this is, so you have to figure out how many '1,000 meters' fit into 4,125 meters.

That's division.

   (4,125 meters) / (1,000 meters)  =  <em>4.125 kilometers</em>


4 0
3 years ago
The ions in most ionic compounds are organized into a
Igoryamba
They are organized into crystals hope i helped
5 0
3 years ago
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