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Paraphin [41]
2 years ago
10

A small metal ball is given a negative charge, then brought near to end a of the rod (figure 1). What happens to end a of the ro

d when the ball approaches it closely this first time?.
Physics
1 answer:
erma4kov [3.2K]2 years ago
7 0

What happens to end a of the rod when the ball approaches it closely this first time is; It is strongly attracted.

<h3>Electrostatics</h3>

I have attached the image of the rod.

We are told that the ball is much closer to the end of the rod than the length of the rod. Thus, if we point down the rod several times, the distance of approach will experience no electric field and as such the charge on end point A of the rod must be comparable in magnitude to the charge on the ball.

This means that their fields will cancel.

Finally, we can conclude that when a charge is brought close to a conductor, the opposite charges will all navigate to the point that is closest to the charge and as a result, a strong attraction will be created.

This also applies to a strong conducting rod and therefore it is strongly attracted.

Read more about Electrostatics at; brainly.com/question/18108470

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A 4.0kg block is sliding with a constant velocity of 3.0m/s on a frictionless table that is 0.5m high. If all of the block’s ene
MArishka [77]

Answer:

Velocity = 4.33[m/s]

Explanation:

The total energy or mechanical energy is the sum of the potential energy plus the kinetic energy, as it is known the velocity and the height, we can determine the total energy.

E_{M}=E_{p}  + E_{k} \\E_{p} = potential energy [J]\\E_{k} = kinetic energy [J]\\where:\\E_{p} =m*g*h\\E_{p} = 4*9.81*0.5=19.62[J]\\E_{k}=\frac{1}{2} *m*v^{2}  \\E_{k}=\frac{1}{2} *4*(3)^{2} \\E_{k}=18[J]\\Therefore\\E_{M} =18+19.62\\E_{M}=37.62[J]

All this energy will become kinetic energy and we can find the velocity.

37.62=\frac{1}{2} *m*v^{2} \\v=\sqrt{\frac{37.62*2}{4} } \\v=4.33[m/s]

8 0
3 years ago
EMERGENCY! PLEASE HELP!
hichkok12 [17]

Answer: Volume = 1080m^3

Explanation:

Given that the prism has a 15 m by 18 m rectangular base and a height of 4 m

Volume is the product of length, breath and height. That is

Volume = L × B × H

Where

L = 18 m

B = 15m

H = 4m

Using the formula above gives:

Volume V = 18 × 15 × 4

V = 1080 m^3

8 0
3 years ago
El resultado de pasar a notación científica la cifra 2 000 000 000 · 10 -15
tensa zangetsu [6.8K]
19,999,985 nomas creo y soy positivo que si es pero puedes ablar ingles
6 0
3 years ago
a student measure the mass of an 8 cm^3 block of brown sugar to be 12.9 g. what is the density of the brown sugar?
schepotkina [342]
Density = mass / volume ;
1 Cubic Centimeter = 0,000001 Cubic Meter
8 cm^3 = 0.000008 m^3
12,9 g = 0,0129 kg


The density is 0,0129 kg/ 0,000008 m^3 = <span><u>1612,5 kg/m^3</u> </span>
4 0
4 years ago
HELP ME
sergij07 [2.7K]

Answer:

13,308 MAYBE IF IT ISN'T IM SO SORRY

Explanation:

6 0
3 years ago
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