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Paraphin [41]
2 years ago
10

A small metal ball is given a negative charge, then brought near to end a of the rod (figure 1). What happens to end a of the ro

d when the ball approaches it closely this first time?.
Physics
1 answer:
erma4kov [3.2K]2 years ago
7 0

What happens to end a of the rod when the ball approaches it closely this first time is; It is strongly attracted.

<h3>Electrostatics</h3>

I have attached the image of the rod.

We are told that the ball is much closer to the end of the rod than the length of the rod. Thus, if we point down the rod several times, the distance of approach will experience no electric field and as such the charge on end point A of the rod must be comparable in magnitude to the charge on the ball.

This means that their fields will cancel.

Finally, we can conclude that when a charge is brought close to a conductor, the opposite charges will all navigate to the point that is closest to the charge and as a result, a strong attraction will be created.

This also applies to a strong conducting rod and therefore it is strongly attracted.

Read more about Electrostatics at; brainly.com/question/18108470

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Anna [14]

Answer:

For the first situation, we first need to find the mass of the second train car.

In order to do that, we apply the conservation of the amount of movement:

515*7.5+m2*0=(m1+m2)*4.8

and we have as a result:

m2 = 289.6875

For the second situation, also we will apply the conservation of the amount of movement:

515*7.5-289.6875*6 = (515+289.6875)*V

and we have as a result:

V = 2.64 (it is moving to the right)

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Is radioactivity on the Earth something relatively new?
luda_lava [24]

naturally occurring radioactive elements have been around since the Earth's formation


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An alpha particle (α), which is the same as a helium-4 nucleus, is momentarily at rest in a region of space occupied by an elect
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Answer:

Explanation:

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1/2 mv² = 3.2 x 10⁻¹⁹ x 3.45 x 10⁻³

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V² = 3.3  x 10⁵

V = 5.74 x 100

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Determine the smallest thickness of the film for which reflected green light of wavelength 540 nm interfere destructively. Expre
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Answer:

Explanation:

Given

Wavelength of green light \lambda =540\ nm

For destructive interference by reflection the path difference is an integral multiple of wavelength so

t=\frac{\lambda '}{2}

where \lambda '=\frac{\lambda }{n}

n=refractive index of medium

suppose water is the medium

so

n=\frac{4}{3}

t=\frac{540\times 3}{4\times 2}

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4 0
4 years ago
2. In these diagrams, the sunlight is coming from the left, as shown by the arrows. Which
RideAnS [48]

Answer:

Explanation:

a) A is accurate because the half of the Moon that is facing the sun is it by the sun, and the other half is dark.

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