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steposvetlana [31]
2 years ago
14

Another question please help ​

Mathematics
1 answer:
finlep [7]2 years ago
5 0

As we know, The slopes of parallel lines are equal.

We are given the lines

\tt \: y = m_{1} x + c \\  \sf \: and \\  \tt \: y =  m_{2}x + c

Their slopes are m1 and m2, So their relation is

\bf \: m_{1} =  m_{2}

  • <em>Thus, Option A is correct!!~</em>
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How many real solutions does this system of equations have? xy = 9<br> y = 3x - 1
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Answer:

two real, unequal roots

Step-by-step explanation:

y is definied as y = 3x - 1.  Substitute 3x - 1 for y in xy = 9, obtaining:

x(3x - 1) = 9.  Then:

3x^2 - x - 9 = 0.  In this quadratic, the coefficients are a = 3, b = -1 and c = -9.

Calculating the discriminant b^2 - 4ac, we get (-1)^2 - 4(3)(-9), or 1 + 108, or 109.  Because the discriminant is positive, we have two real, unequal roots.

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Answer:

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Step-by-step explanation:

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