All categories

2 years ago

Another question please help

Mathematics

1 answer:

finlep [7]2 years ago

5 0

As we know, The slopes of parallel lines are equal.

We are given the lines

$\tt \: y = m_{1} x + c \\ \sf \: and \\ \tt \: y = m_{2}x + c$

Their slopes are m1 and m2, So their relation is

$\bf \: m_{1} = m_{2}$

<em>Thus, Option A is correct!!~</em>

You might be interested in

F(x)=-x^3-x^2+1 what is f(-1)

xxMikexx [17]

-1^3 - -1^2 +1= -1. ...........

8 0

3 years ago

What is 70/6 as a mixed number

bija089 [108]

70/6 is basically saying "divide 70 by 6". So to get to a mixed numer, thats what you have to do.

70/6=11.666666...
(.666666..... is 2/3 as a fraction)

The answer is 11 2/3.

hope i helped!! :))

6 0

3 years ago

Read 2 more answers

What is mass ? is anyone from india ?

kaheart [24]

Answer:Mass is a measure of the amount of matter in an object. I'm not from India, I'm from Maldives!

I'm not trying to be rude with u but

what's wrong with u

I clearly said avyaya

U didn't have to answer!

No need to poke your nose into others business

Mind it

7 0

3 years ago

Read 2 more answers

Which of the following rational functions is graphed below?

Andre45 [30]

We need to see the graph in order to answer

6 0

3 years ago

HELP ASAP A vector starts at point (-3, 4) and ends at point (6, -3). What is the magnitude of the vector? Answer to two decimal

balu736 [363]

The magnitude of the vector to two decimal places is 11.40 units

The formula for calculating the magnitude of the vector is expressed as:

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2 }$

Given the coordinate points (-3, 4) and (6, -3)

$D=\sqrt{(-3-4)^2+(6+3)^2 }\\D=\sqrt{(-7)^2+9^2}\\D=\sqrt{49+81}\\D=\sqrt{130}\\D= 11.40$

Hence the magnitude of the vector to two decimal places is 11.40 units

Learn more here: brainly.com/question/20759497

6 0

2 years ago

Another question please help ​

Another question please help