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Reptile [31]
2 years ago
6

In a chemical reaction, what are the numbers in front of an element called?

Chemistry
1 answer:
sleet_krkn [62]2 years ago
5 0

Answer:

oxidation numbers

Explanation:

chemical equation tells the story of a chemical reaction. Reactants are the starting substances in the reaction while products are the new substances that are formed. The large numbers in front of some of the formulae are called coefficients. These coefficients are used to balance the equation. Chemical reactions must obey the Law of Conservation of Matter. The number of atoms of each element on both sides of the equation must be equal because matter cannot be created or destroyed

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bija089 [108]
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8 0
3 years ago
Why do isotope decay
BaLLatris [955]

Instability

Explanation:

Isotopes decays because they are unstable. Stable isotopes do not decay.

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7 0
2 years ago
To which planet do scientist compare to Kepler-10
Stells [14]
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7 0
3 years ago
The solubility of o2 at 20c is 1.38 x10^-3. the partial presure of o2 in the air at sea level is 0.27 atm. using henery;s law, c
netineya [11]

<u>Answer:</u> The solubility of oxygen at 682 torr is 4.58\times 10^{-3}M

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{A}=K_H\times p_{A}

Or,

\frac{C_{1}}{C_{2}}=\frac{p_{1}}{p_2}

where,

C_1\text{ and }p_1 are the initial concentration and partial pressure of oxygen gas

C_2\text{ and }p_2 are the final concentration and partial pressure of oxygen gas

We are given:

Conversion factor used:  1 atm = 760 torr

C_1=1.38\times 10^{-3}M\\p_1=0.27atm\\C_2=?\\p_2=682torr=0.897atm

Putting values in above equation, we get:

\frac{1.38\times 10^{-3}}{C_2}=\frac{0.27atm}{0.897atm}\\\\C_2=\frac{1.38\times 10^{-3}\times 0.897atm}{0.27atm}=4.58\times 10^{-3}M

Hence, the solubility of oxygen gas at 628 torr is 4.58\times 10^{-3}M

4 0
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Help please!!!! I only have a couple mins
Kaylis [27]

Answer:

D i am prety shure

Explanation:

3 0
2 years ago
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