Answer:
The pressure and maximum height are 
and 161.22 m respectively.
Explanation:
Given that,
Diameter = 3.00 cm
Exit diameter = 9.00 cm
Flow = 40.0 L/s²
We need to calculate the pressure
Using Bernoulli effect
When two point are at same height so ,
....(I)
Firstly we need to calculate the velocity
Using continuity equation
For input velocity,
For output velocity,
Put the value into the formula
(b). We need to calculate the maximum height
Using formula of height
Put the value into the formula
Hence, The pressure and maximum height are and 161.22 m respectively.
Your stomach, as in JUST your stomach?
Well the role of your stomach is to break down large clumps of food. Without that it would be very hard to impossible to digest food.<span />
Answer:
The correct option is;
Still constant
Explanation:
The relative refractive index ₁n₂ between the two medium can be as follows;
Therefore, given that the speed of light in medium 1 is constant and the speed of light on medium 2 is also constant, the relative refractive index ₁n₂ = c₁/c₂ is always constant.
Answer:
h’ = 1/9 h
Explanation:
This exercise must be solved in parts:
* Let's start by finding the speed of sphere B at the lowest point, let's use the concepts of conservation of energy
starting point. Higher
Em₀ = U = m g h
final point. Lower, just before the crash
Em_f = K = ½ m 
energy is conserved
Em₀ = Em_f
m g h = ½ m v²
v_b = 
* Now let's analyze the collision of the two spheres. We form a system formed by the two spheres, therefore the forces during the collision are internal and the moment is conserved
initial instant. Just before the crash
p₀ = 2m 0 + m v_b
final instant. Right after the crash
p_f = (2m + m) v
the moment is preserved
p₀ = p_f
m v_b = 3m v
v = v_b / 3
v = ⅓
* finally we analyze the movement after the crash. Let's use the conservation of energy to the system formed by the two spheres stuck together
Starting point. Lower
Em₀ = K = ½ 3m v²
Final point. Higher
Em_f = U = (3m) g h'
Em₀ = Em_f
½ 3m v² = 3m g h’
we substitute
h’= 
h’ = 
h’ = 1/9 h
The amount of extra electrons present on the negative surface is
57.2 x 
.
Distance =1.6 cm
Side = 24 cm
Electric field = 18000 N/C
Calculating the capacitance in the metal plates is necessary.
Using the capacitance formula
Putting the value
C = 8.85 x 
x (24 x 
/1.6 x
C = 0.318 x 
F
<h3>Calculation of potential</h3>
V = Ed
V = 18000 x 1.6 x V
V = 288 V
<h3>Calculation of charge</h3>
Q = CV
Q = 0.318 x x 288
Q = 91.54 x C
Charge on the both the plates
Q = +91.54 x
Q = - 91.54 x
Calculation of excess electrons on the negative surface:
n = q/e
n = 91.54 x / 1.6 x 
n = 57.2 x electrons
Hence, the number of excess electrons on the negative surface is
57.2 x .
Learn more about capacitance here:
brainly.com/question/14746225
#SPJ4
