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kirill [66]
3 years ago
12

An absent-minded Penn State professor drives from State College to Tyrone, 20 miles away, at 60 mph (miles per hour), before rea

lizing that he forgot his wallet. He immediately returns to State College at 60 mph, picks up his wallet and drives back to Tyrone at 60 mph. Assuming all the travel was done more or less on a straight line and neglecting the time taken to turn around or collect the professor's wallet, what is the magnitude of the professor's average velocity for the entire trip?
Physics
1 answer:
BaLLatris [955]3 years ago
8 0

Answer:20 mph

Explanation:

Given

distance between college to Tyrone=20 miles

Given professor drives with a velocity of 60 mph

he returns to college after reaching tyrone and then again drive to tyrone.

so his net displacement is 20 miles

time taken to cover 20 miles is \frac{1}{3} hr

average velocity=\frac{Displacement}{Time\ taken}

V_{avg}=\frac{20}{\frac{1}{3}+\frac{1}{3}+\frac{1}{3}}

V_{avg}=\frac{20}{1}=20 mph

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Ocean currents are formed by a type of heat transfer that is convection

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The volume electric charge density of a solid sphere is given by the following equation: The variable r denotes the distance fro
qwelly [4]

Answer:

62.8 μC

Explanation:

Here is the complete question

The volume electric charge density of a solid sphere is given by the following equation: ρ = (0.2 mC/m⁵)r²The variable r denotes the distance from the center of the sphere, in spherical coordinates. What is the net electric charge (in μC) of the sphere if the radius of the sphere is 0.5 m?

Solution

The total charge on the sphere Q = ∫∫∫ρdV where ρ = volume charge density = 0.2r² and dV = volume element in spherical coordinates = r²sinθdθdrdΦ

So,  Q =  ∫∫∫ρdV

Q =  ∫∫∫ρr²sinθdθdrdΦ

Q =  ∫∫∫(0.2r²)r²sinθdθdrdΦ

Q =  ∫∫∫0.2r⁴sinθdθdrdΦ

We integrate from r = 0 to r = 0.5 m, θ = 0 to π and Φ = 0 to 2π

So, Q =  ∫∫∫0.2r⁴sinθdθdrdΦ

Q =  ∫∫∫0.2r⁴[∫sinθdθ]drdΦ

Q =  ∫∫0.2r⁴[-cosθ]drdΦ

Q =  ∫∫0.2r⁴-[cosπ - cos0]drdΦ

Q =  ∫∫∫0.2r⁴-[-1 - 1]drdΦ

Q =  ∫∫0.2r⁴-[- 2]drdΦ

Q =  ∫∫0.2r⁴(2)drdΦ

Q =  ∫∫0.4r⁴drdΦ

Q =  ∫0.4r⁴dr∫dΦ

Q =  ∫0.4r⁴dr[Φ]

Q =  ∫0.4r⁴dr[2π - 0]

Q =  ∫0.4r⁴dr[2π]

Q =  ∫0.8πr⁴dr

Q =  0.8π∫r⁴dr

Q =  0.8π[r⁵/5]

Q = 0.8π[(0.5 m)⁵/5 - (0 m)⁵/5]

Q = 0.8π[0.125 m⁵/5 - 0 m⁵/5]

Q = 0.8π[0.025 m⁵ - 0 m⁵]

Q = 0.8π[0.025 m⁵]

Q = (0.02π mC/m⁵) m⁵

Q = 0.0628 mC

Q = 0.0628 × 10⁻³ C

Q = 62.8 × 10⁻³ × 10⁻³ C

Q = 62.8 × 10⁻⁶ C

Q = 62.8 μC

3 0
2 years ago
A space walking astronaut has become detached from her spaceship.shes floating in space while holding a wrench she is thinking a
victus00 [196]

Answer:

Newton's third law of motion states that for every action, there is equal and opposite reaction.

While space walking, when the astronaut gets detached from the space ship, she floats in space holding a wrench. In order to get back to the spaceship, she should throw the wrench in the opposite direction of the spaceship. This action would  cause a reaction on her own body and she would be pushed away from the wrench and towards the spaceship. Thus, she can return back to the spaceship in this way.

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Does wavelength affect the energy of a wave?
Galina-37 [17]

Answer:

Not quite

Explanation:

The frequency of a wave is inversely proportional to its wavelength. That means that waves with a high frequency have a short wavelength, while waves with a low frequency have a longer wavelength

What determines the strength of a wave?

Wave height is affected by wind speed, wind duration (or how long the wind blows), and fetch, which is the distance over water that the wind blows in a single direction. If wind speed is slow, only small waves result, regardless of wind duration or fetch.

So,

As Wavelength increases, The energy of the wave spreads and it decreases

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a car is moving with a velocity of 25m/s for 15s. calculate the displacement of the car. The acceleration of the car over the 15
SpyIntel [72]

Explanation:

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