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kirill [66]
3 years ago
12

An absent-minded Penn State professor drives from State College to Tyrone, 20 miles away, at 60 mph (miles per hour), before rea

lizing that he forgot his wallet. He immediately returns to State College at 60 mph, picks up his wallet and drives back to Tyrone at 60 mph. Assuming all the travel was done more or less on a straight line and neglecting the time taken to turn around or collect the professor's wallet, what is the magnitude of the professor's average velocity for the entire trip?
Physics
1 answer:
BaLLatris [955]3 years ago
8 0

Answer:20 mph

Explanation:

Given

distance between college to Tyrone=20 miles

Given professor drives with a velocity of 60 mph

he returns to college after reaching tyrone and then again drive to tyrone.

so his net displacement is 20 miles

time taken to cover 20 miles is \frac{1}{3} hr

average velocity=\frac{Displacement}{Time\ taken}

V_{avg}=\frac{20}{\frac{1}{3}+\frac{1}{3}+\frac{1}{3}}

V_{avg}=\frac{20}{1}=20 mph

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Answer

given,

distance = 140 m

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b) a = \dfrac{v-u}{t}

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