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3 years ago

Describe the structure of atoms including locations and changes of protons,neutrons,and electrons

1 answer:

8 0

Atoms are made up of three basic particles: protons, electrons, and neutrons. Protons and neutrons are found in the nucleus, and the nucleus is found in the very center of an atom. Protons are positively charged whereas neutrons have no charge.

Electrons are found on the electron shells, and the electron shells are found in in the outermost region of an atom. The outermost electron shell contains valence electrons. Electrons are negatively charged.

The number of protons vary depending on the atomic number of an atom. The number of neutrons vary depending on the atomic mass and atomic number of an atom. To find the neutron you must subtract the atomic mass from the atomic number. The number of electrons in a neutral atom also vary depending on the atomic number.

Sorry this is so long. I didn't quite understand your question so I added the last paragraph in just in case it was helpful in any way. I hope I helped!

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determine the freezing point depression of a solution that contains 30.7 g glycerin (c3h8o3, molar mass

Blababa [14]

The freezing point depression of a solution containing 30.7 g of glycerin is calculated as -1.65°C

Equating :

It is given that,

Given mass of glycerin is = 30.7 grams (Solute)

Volume of water = 376 mL

$K_{f}$ or molar -freezing-depression point is = 1.86°C/m

Molar mass of glycerin = 92.09 g/mole

Now, to work out the value, the mass of water should be known. Thus, to calculate, the formula used will be:

Mass = Density X Volume

Mass = 1.0 g/mL X 376 mL

Mass = 376 g or 0.376 Kg

Using the formula of melting point depression, the equation becomes:

Δ $T_{f}$ = i × $K_{f}$ ×m

T⁰- $T_{s}$ = $i *K_{f} *\frac{mass of glycerin}{molar mass of glycerin * mass of water in kg}$

in which,

Δ $T_{f}$ = change in freezing point

Δ $T_{s}$ = freezing point of solution that has to be find

ΔT° = freezing point of water ()

Since, glycerin is a non-electrolyte, the Van't Hoff factor will be 1.

Substituting the values in the above equation:

0⁰C₋T $_{s}$ = 1 ×1.86°C/m × $\frac{30.7}{92.09g/mol * 0.376kg}$

$T_{s}$ = -1.65°C

Thus, the freezing point depression of a solution is -1.65°C

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Freezing point depression

Freezing point depression is a colligative property observed in solutions that results from the introduction of solute molecules to a solvent. The freezing points of solutions are all less than that of the pure solvent and is directly proportional to the molality of the solute

Is melting point elevation or depression?

Boiling point elevation is that the raising of a solvent's boiling point due to the addition of a solute. Similarly, melting point depression is the lowering of a solvent's freezing point due to the addition of a solute. In fact, because the boiling point of a solvent increases, its melting point decreases

Learn more about freezing point depression :

brainly.com/question/26525184

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8 0

8 months ago

Which statement best explains what causes the phase change from solid ice to liquid water?

Fofino [41]

It would be c because it has to get hot so it is absorbing the heat not releasing it

6 0

2 years ago

An atom contains 5 protons, 6 neutrons, and 6 electrons. What is the mass number of this atom? *

Tju [1.3M]

Answer:

here you go

Explanation:

Atomic Number (Z) = Mass Number (A) - Number of Neutrons An atom has 5 protons, 5 electrons and 6 neutrons The atomic number = number of protons = number of electrons = 5 The mass number = 5 protons + 6 neutrons = 11

6 0

2 years ago

State the formula of an alkane with 100 carbon atoms

Kitty [74]

Answer:

C100H202

Explanation:

this alkane is referred as n- hectane

4 0

2 years ago

The heat required to raise the temperature of 12g of water from 16 C to 21 C is:

NemiM [27]

Answer:

The heat required to raise the temperature of 12g of water from 16 C to 21 C is 60 cal.

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

There is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

Q=?
c= 4.186 $\frac{J}{g*C}$
m= 12 g
ΔT=Tfinal - Tinitial= 21 °C - 16°C= 5 °C

Replacing:

Q= 4.186 $\frac{J}{g*C}$ *12 g *5 °C

Solving:

Q=251.16 J

Since 1 J is equal to 0.2388 cal, then the following rule of three can be applied: if 1 J is equal to 0.2388 cal, then 251.16 J to how many cal are?

$cal=\frac{251.16 J * 0.2388 cal}{1 J}$

cal= 59.98 ≅ 60

The heat required to raise the temperature of 12g of water from 16 C to 21 C is 60 cal.

3 0

2 years ago