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Anit [1.1K]
3 years ago
15

HELP THIS IS DUE SOON!!!

Mathematics
1 answer:
slamgirl [31]3 years ago
5 0

Answer:

N=11

Step-by-step explanation:

Multiply both sides

than move the constant to the right

then calculate

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Write a translation rule that maps point D ( 7 , − 3 ) onto point D ' ( 2 , 5 ). I NEED HELPPPP!
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Answer:

T_{ - 5 ,8} \: or \: D'(x,y) →D(x - 5,y + 8)

Step-by-step explanation:

T _ { ? ,?}

D'(x,y) →D(x \pm ?,y \pm ?)

given D : (7,-3), and D' : (2,5)

the coordinates of D can be represented as (x1,y1), and the coordinates of D' can be represented as (x,y).

you can simply take the difference in the x values and difference in the y values from the preimage to image.

like this:

f'(x,y) → f(x+(x-x1),y+(y-y1)) : T _ {(x-x_1),(y-y_1)}

D'(x,y) → D(x+(2-7),y+(5--3))

D'(x,y) → D(x<u>-5</u>,y<u>+8</u>) : T _ {-5 ,8}

7 0
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Help me please! If you DO decide to help, please explain it to me since I'm extremely confused! THANK YOU!
den301095 [7]

\bf \cfrac{(-4x^2)(2x^{-2}y)^3}{(16x^5)(4y^3)^2}\implies \cfrac{(-4x^2)(2^3x^{-2\cdot 3}y^3)}{(16x^5)(4^2y^{3\cdot 2})}\implies \cfrac{(-4x^2)(8x^{-6}y^3)}{(16x^5)(16y^6)} \\\\\\ \cfrac{-32x^{2-6}y^3}{256x^5y^6}\implies -\cfrac{x^{-4} y^3}{8x^5y^6}\implies -\cfrac{1}{8x^5x^{4}y^6y^{-3}}\implies -\cfrac{1}{8x^{5+4}y^{6-3}} \\\\\\ -\cfrac{1}{8x^9y^3}

8 0
3 years ago
Read 2 more answers
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