Ask question

Ask question

All categories

3 years ago

9

why is it important for digestive system functions that mucous membranes can secrete and absorb susbstances?

1 answer:

MissTica3 years ago

6 0

Answer:

It pushes food through the GI tract. The inside of GI tract is lined with mucous membranes. Mucous membranes are moist tissues that can secrete and absorb substances. The ability to secrete and absorb substances is necessary for the functions of the digestive system.

Explanation:

Can I have brainliest?

You might be interested in

A light bulb has a resistance of 100 ohms. If a current of 1.2 amps is going through it, calculate

inysia [295]

Answer: 120 volts

Explanation:

5 0

3 years ago

Which of the following is the proper unit for measuring power? Newton Joules Watts Meters

fredd [130]

The unit for power is Watts. the newton is a unit for force. joules for energy and meters for distance

3 0

3 years ago

Can someone please help me come up with a hypothesis?. The question that I have is "How many sugars are in your smoothies?"

patriot [66]

'I believe that there is 20 grams of sugar in the smoothies.'

I don't know, just an idea.

8 0

3 years ago

Read 2 more answers

bogdanovich [222]

C. unbalanced is the correct answer for newton's first law.

8 0

2 years ago

Read 2 more answers

Parallel rays of monochromatic light with wavelength 571nm illuminate two identical slits and produce an interference pattern on

Natasha2012 [34]

Answer:

$8.8\times 10^{-6} W/m^2$

Explanation:

We are given that

Wavelength, $\lambda=571 nm=571\times 10^{-9} m$

$1 nm=10^{-9} m$

R=75 cm= $\frac{75}{100}=0.75 m$

1 m=100 cm

$d=0.640 mm=0.64\times 10^{-3} m$

$1 mm=10^{-3} m$

$a=0.434 mm=0.434\times 10^{-3} m$

$y=0.830 mm=0.830\times 10^{-3} m$

$I_0=5.00\times 10^{-4}W/m^2$

$tan\theta=\frac{y}{R}$

$\theta=\frac{0.830\times 10^{-3}}{0.75\times 10^{-2}}$

$\theta=1.1\times 10^{-3}rad$

$tan\theta\approx \theta$

Because $\theta$ is small.

$\phi=\frac{2\pi dsin\theta}{\lambda}$

$\sin\theta\approx \theta$ ,

Therefore

$\phi=\frac{2\times\pi\times 0.64\times 10^{-3}\times 1.1\times 10^{-3}}{571\times 10^{-9}}$

$\phi=7.74 rad$

$\beta=\frac{2\pi a\theta}{\lambda}$

$\beta=5.3 rad$

$I=I_0cos^2(\frac{\phi}{2})(\frac{sin\frac{\beta}{2}}{\frac{\beta}{2}})^2$

$I=5\times 10^{-4}cos^2(\frac{7.74}{2})(\frac{sin\frac{5.3}{2}}{\frac{5.3}{2}})^2$

$I=8.8\times 10^{-6} W/m^2$

6 0

3 years ago