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mafiozo [28]
3 years ago
8

The half life of carbon 14 is 5730 years what fraction of the original c14 would you expect to be present in a fossil that is 28

,650 years old
Chemistry
1 answer:
Bogdan [553]3 years ago
7 0
The half-life of a radioisotope describes the amount of time required for one-half of the isotope to decay into a daughter atom. After one half-life, 50% remains; after two, 25%, and so on.

To find how many half-lives have passed in 28,650 years, we can divide it by the time it takes for one half-life to pass. This reveals that five half-lives have passed.

HL ———— 1 2 3 4 5
% remain - 50 25 12.5 6.25 3.125

After 28,650 years or 5 half-lives, 3.125% of the original radioisotope remains in the fossil.
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A big bang occurred in the solar system as a resultof a fusion reaction.All matter I the solar system had been clumped together was shattered and sent flying. As new pieces of matter connected, all the celestial bodies the solar system were formed

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How does the use of hydroelectric energy compare to the use of coal?
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Which one of the following will change the value of an equilibrium constant?
Ad libitum [116K]

Answer:

(E) changing temperature

Explanation:

Consider the following reversible balanced reaction:

aA+bB⇋cC+dD

If we know the molar concentrations of each of the reaction species, we can find the value of Kc using the relationship:

Kc = ([C]^c * [D]^d) / ([A]^a * [B]^b)

where:

[C] and [D] are the concentrations of the products in the equilibrium; [A] and [B] reagent concentrations in equilibrium; already; b; c and d are the stoichiometric coefficients of the balanced equation. Concentrations are commonly expressed in molarity, which has units of moles / 1

There are some important things to remember when calculating Kc:

-  <em>Kc is a constant for a specific reaction at a specific temperature</em>. If you change the reaction temperature, then Kc also changes

- Pure solids and liquids, including solvents, are not considered for equilibrium expression.

- The reaction must be balanced with the written coefficients as the minimum possible integer value in order to obtain the correct value of Kc

8 0
3 years ago
How many moles of helium are 8.84×10^24 atoms of He?
viva [34]

Answer:

14.77 mol.

Explanation:

  • It is known that every 1.0 mole of compound or element contains Avogadro's number (6.022 x 10²³) of molecules or atoms.

<u><em>Using cross multiplication:</em></u>

1.0 mole of He contains → 6.022 x 10²³ atoms.

??? mole of He contains → 8.84 x 10²⁴ atoms.

<em>∴ The no. of moles of He contains (8.84 x 10²⁴ atoms) </em>= (1.0 mol)(8.84 x 10²⁴ atoms)/(6.022 x 10²³ atoms) =<em> 14.77 mol.</em>

8 0
3 years ago
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