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KatRina [158]
3 years ago
13

What is the ground-state electronic configuration of a chlorine anion (cl—)?

Chemistry
1 answer:
Natasha2012 [34]3 years ago
6 0
Ground state just means the normal state, so the configuration of Cl- is 2, 8, 8.
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Convertible bonds are examples of: a. Securities that have characteristics of both debt and equity b. Non-recurring items c. Ass
iren2701 [21]

Answer:

a. Securities that have characteristics of both debt and equity

Explanation:

A convertible bond is a debt security that can be converted into a certain number of shares and this can be done during specific times in the life of the bond. According to this, convertible bonds are examples of securities that have characteristics of both debt and equity as they are a type of debt that pays interest but can be turned into shares.

5 0
3 years ago
The distance from Santa Maria to Los Alamos is 16.25 mi. what is the distance in meters?
Radda [10]

Answer:

26,167.47m

Explanation:

Problem:

We are to solve this problem using dimensional analysis:

  from the given conversion factors-

      0.621mi = 1.00km

       1km = 1000m

From the problem, we are groing from miles to metres:

      16.25mi x \frac{1km}{0.621mi} x \frac{1000m}{1km}

The mi will cancel out and also the km. This leaves us with the desired unit we want which is meters, m.

       =  26,167.47m

7 0
3 years ago
If 20.0 g of NaOH is added to 0.750 L of 1.00 M Cd(NO₃)₂, how many grams of Cd(OH)₂ will be formed in the following precipitatio
bulgar [2K]

Answer:

m_{Cd(OH)_2}=36.6 gCd(OH)_2

Explanation:

Hello.

In this case, for the given chemical reaction, in order to compute the grams of cadmium hydroxide that would be yielded, we must first identify the limiting reactant by computing the yielded moles of that same product, by 20.0 grams of NaOH (molar mass = 40 g/mol) and by 0.750 L of the 1.00-M solution of cadmium nitrate as shown below considering the 1:2:1 mole ratios respectively:

n_{Cd(OH)_2}^{by\ NaOH}=20.0gNaOH*\frac{1molNaOH}{40gNaOH} *\frac{1molCd(OH)_2}{2molNaOH} =0.25molCd(OH)_2\\\\n_{Cd(OH)_2}^{by\ Cd(NO_3)_2}=0.750L*1.00\frac{molCd(NO_3)_2}{L}*\frac{1molCd(OH)_2}{1molCd(NO_3)_2}  =0.75molCd(OH)_2

Thus, since 20.0 grams of NaOH yielded less of moles of cadmium hydroxide, NaOH is the limiting reactant, therefore the mass of cadmium hydroxide (molar mass = 146.4 g/mol) is:

m_{Cd(OH)_2}=0.25molCd(OH)_2*\frac{146.4gCd(OH)_2}{1molCd(OH)_2} \\\\m_{Cd(OH)_2}=36.6 gCd(OH)_2

Best regards.

4 0
3 years ago
Based on the table, which do you think is larger – your direct water use or your indirect water use?
Pavlova-9 [17]

Answer:

your indirect water use.

5 0
4 years ago
Which of the following describes the electron sharing between two oxygen atoms? Each oxygen shares one electron with the other.
Troyanec [42]
I believe each oxygen shares 2 elections with the other.
5 0
3 years ago
Read 2 more answers
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