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LiRa [457]
2 years ago
7

Solve:

Mathematics
2 answers:
liraira [26]2 years ago
8 0

Answer:

I hope it'll help you...

Leni [432]2 years ago
4 0

To prove :

\sqrt{ \frac{1 + cosθ}{1 - cosθ}} =  cosecθ+cotθ

Solution:

L.H.S. =  \sqrt{ \frac{1+cosθ}{1−cosθ}}

Multiplying numerator and denominator with 1+cos θ we get,

=  \sqrt{ \frac{1+cosθ}{1−cosθ } \times\frac{1+cosθ}{1+cosθ} }

=  \sqrt{ \frac{(1 + cosθ {)}^{2} }{1 - cos^{2} θ} }

= \sqrt{ \frac{(1+cosθ)^{2}}{sin^{2}θ}  }

=  \frac{1+cosθ}{ \sinθ}

=  \frac{1}{sinθ} +  \frac{ \cosθ}{sinθ}

=cosec \: θ+cot \: θ

= R.H.S.

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