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3 years ago

What element/compounds are used in the melting of ice?

1 answer:

8 0

The temperature of the air, pavement, and the type of ice-melt compound used will affect the rate at which the ice melts. There are many different ice-melt compounds available from traditional rock salt (sodium chloride) to ice-melt pellets (calcium chloride).

You might be interested in

write chemical equations of photosynthesis and cellular respiration and show if carbon is oxidized or reduced

irina [24]

Answer:

Explanation:

The chemical reaction for cellular respiration is as follows -

C₆H₁₂O₆ ( Glucose ) + 6 O₂ ( Oxygen ) --------------> 6CO₂ ( Carbon dioxide ) + 6H₂O ( Water ) + 38 ATP molecules ( Energy ) .

This is an example of oxidation of carbon .

The chemical reaction for photosynthesis is as follows -

6CO₂ ( Carbon dioxide ) + 6H₂O ( Water ) --------------> C₆H₁₂O₆( Glucose ) + 6 O₂ ( Oxygen ).

This is an example of reduction of carbon .

6 0

2 years ago

What mass of carbon dioxide is formed when 1.75 mol of ethane burns completely in oxygen?

dybincka [34]

Answer:

There is a mass of 154 Grams of Carbon Dioxide.

Explanation:

One mole is equal to 6.02 × 10^23 particles.

This means we have 1.05 X 10^24 total particles of Ethane.

Each ethane particle contains 2 carbon atoms.

If every particle of ethane is burned, we will end up with 2.10 x 10^24 molecules of Carbon Dioxide (Particles of Methane x 2, since each Methane particle contains 2 carbon atoms)

Carbon Dioxide has a molar mass of 44.01 g/mol

So if we take our amount of Carbon Dioxide molecules and divide it by 1 mole, ((2.10 x 10^24)/(6.02 x 10^23) = 3.49) we find that we have 3.49 moles of Carbon Dioxide.

Now all we need to do is multiply our moles of carbon dioxide(3.49) by it's molar mass(44.01) while accounting for significant digits.

What you should end up with is 154 Grams of Carbon Dioxide.

Hope this helps (And more importantly I hope I didn't make any errors in my math lol)

As a side note this is all assuming that this takes place at STP conditions.

3 0

3 years ago

What is the temperature of 4.5 moles of a gas that occupies 50. mL at 1.35 atm?

devlian [24]

Answer:

$T = 0.182$ Kelvin

Explanation:

As we know that

$PV = nRT\\$

Where P is the pressure in atmospheric pressure

T is the temperature in Kelvin

R is the gas constant

V is the volume in liters

$R = 0.08206$

Substituting the given values in above equation, we get -

$1.35 * \frac{50}{1000}= 4.5 * 0.08206* T\\$

On rearranging, we get

$T = \frac{1.35*50}{1000*0.08206*4.5} \\$

$T = 0.182$ Kelvin

7 0

2 years ago

How do you balance the equation Hydrogen plus Oxygen yield water?

Andre45 [30]

Hey there! Hello!

Not sure if you still need the answer to this question, but I'd love to help out if you do.

So, the way to balance this equation is pretty simple. First, you need to keep in mind that molecules of hydrogen and oxygen do not come in single molecules, but in bonded pairs, represented by H2 and O2.

$H2+O2=H2O$

But, that's incorrect. The combination of 2 hydrogen molecules with 1 oxygen molecule yields water, but that leaves one oxygen molecule leftover. When broken down, this is how many of each molecule is on each side of the previously stated equation:

Left:
H: 2
O: 2

Right:
H: 2
O: 1

So we have to multiply H2O on the right side by 2 in order to get this:

$H2+O2=2(H2O)$

Left:
H: 2
O: 2

Right:
H: 4
O: 2

The last step is to multiply H2 on the left by two to make it match up with the right side, balancing the equation:

$2(H2)+O2=2(H2O)$

Left:
H: 4
O: 2

Right:
H: 4
O: 2

That makes our equation balanced! I hope this helped you out, feel free to ask any additional questions if you need further clarification. :-)

5 0

3 years ago

Determine the location of the last significant place value by placing a bar over the digit.

Vlad1618 [11]

Answer:

8,040

0.0300

699.5

2.000 x 102

0.90100

90, 100

4.7 x 10-8

10,800,000.0

3.01 x 1021

0.000410

Explanation:

First remember the following rules of determining the last significant place value :

1. The digits from 1-9 are all significant and zeros between significant digits are also significant.

2. The trailing or ending zeroes are significant only in case of a decimal number otherwise they are ignored. However starting zeroes of such a number are not significant.

Now observing above rules, lets determine the location of the last significant place value of each given example. I am determining the location by turning the last significant place to bold.

1) 8,040

8,040

Location of the last significant place value is 3 and bar is over last significant digit that is 4. Number is not decimal so ending zero is ignored. Every non zero digit is a significant.

2) 0.0300

0.0300

Location is 3 and bar is over 0. Number has a decimal point so ending zero is not ignored but starting zeroes are ignored.

3) 699.5

699.5

Location is 4 and bar is over 5.

4) 2.000 x 10²

2.000 x 10²

Location is 4 and bar is over 0. This is because the number is decimal so trailing zeroes cannot be ignored. Also if we convert this number it becomes:

200.0 so last significant digit is 0 and location of last significant digit is 4.

5) 0.90100

0.90100

Location is 5 and bar is over 0. This is because in a number with decimal point starting zeroes are ignored but trailing zeroes after decimal point are not ignored. So we count from 9 and last significant digit is 0.

6) 90, 100

90, 100

Location is 3 and bar is over 1. This is because it is not a number with decimal point. So the trailing zeroes are ignored. The count starts from 9 and last significant is 1.

7) 4.7 x 10⁻⁸

4.7 x 10⁻⁸

Location is 2 and bar is over 7. This is because the starting zeroes in a number with a decimal point are ignored. So the first digit considered is 4 and last significant digit is 7. If we expand this number:

4.7 x 10⁻⁸ = 0.000000047 = 0.000000047

Here the starting zeroes are ignored because there is a decimal point in the number.

8) 10,800,000.0

10,800,000.0

Location is 9 and bar is over 0. Number has a decimal point so ending zero is not ignored and last significant figure is 0.

However if the number is like:

10,800,000. Then location would be 8 and bar is over 0.

9) 3.01 x 10²¹

3.01 x 10²¹

Location is 3 and bar is over 1. Lets expand this number first

3.01 x 10²¹ = 3.01 x 1000000000000000000000

= 3010000000000000000000

So this is the number:

3010000000000000000000

Since this is number does not have a decimal point so the trailing zeroes are ignored. Hence the count starts from 3 and the last significant figure is 1

10) 0.000410

0.000410

Location is 3 and bar is over 0. This is because the number has a decimal point so the ending zero is not ignored but the starting zeroes are ignored according to the rules given above. Hence the first significant figure is 4 and last significant figure is 0.

6 0

3 years ago