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Sergeeva-Olga [200]
2 years ago
7

A ball with a mass of 1 kg is moving in a straight line at the same speed as a ball with a mass of 10 kg. Both balls are brought

to rest in 4.0 seconds. What is true of the force required to stop the balls?
A. It takes less force to stop the 1 kg ball because it has less inertia


B. It takes more force to stop the 1 kg ball because it has more inertia.

C. It takes the same force to stop both balls because they are moving at the same speed.

D. It takes less force to stop the 10 kg ball because it has less inertia.
Physics
2 answers:
Alenkasestr [34]2 years ago
7 0

Answer:

A it takes less force to stop the 1 kg ball because it has less inerita

Explanation:

Ronch [10]2 years ago
7 0
A. It takes less force to stop a 1 kilogram ball bc it has less inertia
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A bolt is dropped from a bridge under construction, falling 96 m to the valley below the bridge. (a) How much time does it take
irakobra [83]

Answer:

a)It takes the bolt 0.25 s to pass the last 11% of the fall.

b)When the bolt begins to fall the last 11% of the fall its velocity is -41.2 m/s.

c)The velocity of the bolt just before it reaches the ground is -43.6 m/s

Explanation:

Hi there!

a) Let´s calculate how much distance it is the last 11% of the fall:

96 m · 0.11 = 10.56 m

So, we have to find how much time it takes the bolt to pass from a height of 10.56 m to the ground.

First, let´s calculate how much time it takes the bolt to reach a height of 10.56 m. For that we can use this equation:

h = h0 + v0 · t + 1/2 · g · t²

Where:

h = height of the bolt at a time t.

h0 = initial height.

v0 = initial velocity.

t = time.

g = acceleration due to gravity.

If we consider the ground as the origin of the frame of reference, then h0 = 96 m. Since the bolt is dropped, the initial velocity is zero (v0 = 0). Then, the equation gets reduce to this:

h = h0 + 1/2 · g · t²

We have to find at which time h = 10.56 m.

10.56 m = 96 m - 1/2 · 9.8 m/s² · t²

Solving for t:

√(-2 · (10.56 m - 96 m) / 9.8 m/s²) = t

t = 4.2 s

Now that we have the time at which the bolt is located at 10.56 m above the ground, we can calculate the velocity of the bolt at that time.

The equation of velocity (v) of the bolt is the following:

v = v0 + g · t

at t = 4.2 s.

v = 0 - 9.8 m/s² · 4.2 s

v = -41.2 m/s

<u>When the bolt begins to fall the last 11% of the fall its velocity is -41.2 m/s.</u>

Now, we can calculate how much time it takes to fall the last 10.56 m.

The initial velocity of the bolt will be the velocity at h = 10.56 m. The initial height will be 10.56 m.

h = h0 + v0 · t + 1/2 · g · t²

We have to find the time at which h = 0 (the bolt hits the ground)

0 = 10.56 m - 41.2 m/s · t - 1/2 · 9.8 m/s² · t²

Solving the quadratic equation using the quadratic formula:

t = 0.25 s (the other solution of the quadratic equation is negative and thus discarded).

<u>It takes the bolt 0.25 s to pass the last 11% of the fall.</u>

Now, let´s calculate the velocity of the bolt when it reaches the ground:

v = v0 + g · t

v = -41.2 m/s - 9.8 m/s² · 0.25 s

v = -43.6 m/s

<u>The velocity of the bolt just before it reaches the bolt is -43.6 m/s</u>

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