2 years ago

If kinetic energy of a body is decreased by 10percent then decrease in linear momentum of that body

Physics

1 answer:

algol [13]2 years ago

7 0

Answer:

E = 1/2 M V^2 = 1/2 P V since P = M V

E2 / E1 = P2 V2 / (P1 V1)

P2 / P1 = E2 V1 / (E1 V2) = V2^2 V1 / (V1^2 V2) = V2 / V1

E2 / E1 = V2^2 / V1^2

V2 / V1 = (E2 / E1)^1/2

V2 / V1 = (.9)1/2 = .95

The linear momentum would have to decrease by 5%

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3 years ago

A camera takes a properly exposed photo with a 4.0 mm diameter aperture and a shutter speed of 1/1000 s. If the photographer foc

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option E

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$log_2(\dfrac{N^2}{t_1})=log_2(\dfrac{N^2}{t_2})$

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3 years ago

During 57 seconds of use, 330 C of charge flow through a microwave oven. Compute the size of the electric current.

swat32

Answer:

5.78amps

Explanation:

Given data

Time t= 57 seconds

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Current I= ??

The expression for the electric current is given as

Q= It

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3 years ago

If kinetic energy of a body is decreased by 10percent then decrease in linear momentum of that body​

If kinetic energy of a body is decreased by 10percent then decrease in linear momentum of that body