Initial velocity of object vi=10.0 cm/s
initial position fo vector of the object is xi=3.09 cm
Final position of vector xf=-5.00cm
then displacement of object s = xf-xi=-5.00-3.09=-8.09cm
time t=2.55 s
s=vit+1/2at2
-5.00 = 11*2.55+1/2*a2.552
a = (-5.00 - 10*2.55*2)/2.552 = 2.94 cm
Acceleration is 2.94 cm.
<h3>What is a
cceleration?</h3>
Speed increase is the name we provide for any cycle where the speed changes. Since speed is a speed and a bearing, there are simply two different ways for you to speed up: change your speed or shift your course or change both. In mechanics, speed increase is the pace of progress of the speed of an item concerning time. Speed increases are vector amounts. The direction of an item's speed increase is given by the direction of the net power following up on that article. An item's typical speed increase throughout some stretch of time is its adjustment of speed separated by the term of the period. Numerically, quick speed increase, in the meantime, is the constraint of the typical speed increase over a little time period. In the terms of analytics, immediate speed increase is the subordinate of the speed vector concerning time.
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Answer:
False.
Separation between channel is required when frequency division multiplexing (FDM) is used to aggregate several modulated channels together.
Explanation:
In Frequency Division Multiplexing (FDM), the total bandwidth is divided to a set of frequency bands that do not overlap. Each of these bands is a carrier of a different signal that is generated and modulated by one of the sending devices.
The frequency bands are separated from one another by strips of unused frequencies called the guard bands, to prevent overlapping of signals.
The modulated signals are combined together using a multiplexer (MUX) in the sending end. The combined signal is transmitted over the communication channel, thus allowing multiple independent data streams to be transmitted simultaneously. At the receiving end, the individual signals are extracted from the combined signal by the process of demultiplexing (DEMUX).
Answer:
Velocity of airplane is 500 km/h
Velocity of wind is 40 km/h
Explanation:
= Velocity of airplane in still air
= Velocity of wind
Time taken by plane to travel 1150 km against the wind is 2.5 hours

Time taken by plane to travel 450 km against the wind is 50 minutes = 50/60 hours

Subtracting the two equations we get

Applying the value of velocity of wind to the first equation

∴ Velocity of airplane in still air is 500 km/h and Velocity of wind is 40 km/h