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krek1111 [17]
3 years ago
5

Two sacks contain the same number of identical apples and are separated by a distance r. The two sacks exert a gravitational for

ce on each other that is opposite in direction but with the same magnitude, F. Half the apples are removed from one sack and placed in the second sack. What is the magnitude of the gravitational force between the two sacks in terms of the original force, F?​
Physics
1 answer:
stepan [7]3 years ago
3 0

Answer:

Explanation:

im sleppy

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A total charge of 4.70 is distributed on two metal spheres. When the spheres are 10 cm apart, they each feel a repulsive force o
Anna35 [415]

Answer:0.114 C

Explanation:

Given

Total 4.7 C is distributed in two spheres

Let q_1 and q_2 be the charges such that

q_1+q_2=4.7

and Force between charge particles is given by

F=\frac{kq_1q_2}{r^2}

4.7\times 10^11=\frac{9\times 10^9\times q_1\cdot q_2}{0.1^2}

q_1\cdot q_2=0.522

put the value of q_1

q_2\left ( 4.7-q_2\right )=0.522

q_2^2-4.7q_2+0.522=0

q_2=\frac{4.7\pm \sqrt{4.7^2-4\times 1\times 0.522}}{2}

q_2=0.114 C

thus q_1=4.586 C

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