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seropon [69]
3 years ago
12

the wheel of a car has a radius of .350 m. the engine of the car applies applies a torque of 295 N m to this wheel, which does n

ot slip against the road surface. since the wheel does not slip the road must be appplying a force of static friction to the wheel that produces a countertorque. moreover, the car has a constant velocity so this countertorque balances the applied torque. what is the magnitude of the static frictional force?
Physics
1 answer:
maria [59]3 years ago
6 0

The magnitude of static friction force is f_s = 842.8 N

Explanation:

Write down the values given in the question

The wheel of a car has radius r = 0.350 m

The car applies the torque is τ = 295 N m

It is said that the wheels does not slip against the road surface,

Here we apply a force of static friction,

It can be calculated as  

Frictional force f_s = τ / r

                            = 295 Nm / 0.350 m

                            f_s = 842.8 N

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Answer:

The correct option is: Total energy

Explanation:

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The Hamiltonian operator was named after the Irish mathematician, William Rowan Hamiltonis denoted and is denoted by H.

3 0
3 years ago
A cat with a mass of 5.00 kg pushes on a 25.0 kg desk with a force of 50.0N to jump off. What is the force on the desk?
olya-2409 [2.1K]

Answer:

First of all the formula is F= uR,( force= static friction× reaction)

mass= 5+25=30

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u= ?

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3 years ago
You drop a steel ball bearing, with a radius of 2.40 mm, into a beaker of honey. Note that honey has a viscosity of 6.00 Pa/s an
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\text { Steel has a density } \rho=7800 \mathrm{kg} / \mathrm{m}^{3}

\left.\mathrm{g}=9.8 \mathrm{m} / \mathrm{s}^{2} \text { (g is referred to as the acceleration of gravity. Its value is } 9.8 \mathrm{m} / \mathrm{s}^{2} \text { on Earth }\right)

While calculating the terminal speed in liquids where density is high the stokes law is used for viscous force and buoyant force is taken into consideration for effective weight of the object. So the expression for terminal speed (Vt)

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\mathrm{V}_{\mathrm{t}}=\frac{2 \times 0.0024^{2}(7800-1360) 9.8}{9 \times 6}

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3 years ago
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