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Titanium is the correct answer.
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Answer:
The mass of solution will be "395.78 g".
Explanation:
Given:
Mass of acetic acid,
= 30 g
Percentage,
= 7.58% w/w
Now,
⇒ % ![=\frac{Mass \ of \ acetic \ acid}{Mass \ of \ solution}\times 100](https://tex.z-dn.net/?f=%3D%5Cfrac%7BMass%20%5C%20of%20%5C%20acetic%20%5C%20acid%7D%7BMass%20%5C%20of%20%5C%20solution%7D%5Ctimes%20100)
By putting the values, we get
⇒ ![7.58=\frac{30}{Mass \ of \ solution}\times 100](https://tex.z-dn.net/?f=7.58%3D%5Cfrac%7B30%7D%7BMass%20%5C%20of%20%5C%20solution%7D%5Ctimes%20100)
⇒ ![Mass \ of \ solution=\frac{30\times 100}{7.58}](https://tex.z-dn.net/?f=Mass%20%5C%20of%20%5C%20solution%3D%5Cfrac%7B30%5Ctimes%20100%7D%7B7.58%7D)
⇒ ![=\frac{3000}{7.58}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B3000%7D%7B7.58%7D)
⇒
<span>Acid is a molecule capable of
donating hydrogen ion and they form aqueous solutions with a sour taste while
base is a substance that accepts proton from proton donor and in aqueous solution,
they have an astringent or bitter taste. Moreover, a good example for base is
sodium hydrogen carbonate as baking soda or baking powder and for acid, the
most common example is the acetic acid or vinegar.</span>
Answer: There are 7.4 moles of helium gas present in a 1.85 liter container at the same temperature and pressure.
Explanation:
Given:
= 2.25 L,
= 9.0 mol
= 1.85 L,
= ?
Formula used to calculate the moles of helium are as follows.
![\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\](https://tex.z-dn.net/?f=%5Cfrac%7BV_%7B1%7D%7D%7Bn_%7B1%7D%7D%20%3D%20%5Cfrac%7BV_%7B2%7D%7D%7Bn_%7B2%7D%7D%5C%5C)
Substitute the values into above formula as follows.
![\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{2.25 L}{9.0 mol} = \frac{1.85 L}{n_{2}}\\n_{2} = \frac{1.85 L \times 9.0 mol}{2.25 L}\\= 7.4 mol](https://tex.z-dn.net/?f=%5Cfrac%7BV_%7B1%7D%7D%7Bn_%7B1%7D%7D%20%3D%20%5Cfrac%7BV_%7B2%7D%7D%7Bn_%7B2%7D%7D%5C%5C%5Cfrac%7B2.25%20L%7D%7B9.0%20mol%7D%20%3D%20%5Cfrac%7B1.85%20L%7D%7Bn_%7B2%7D%7D%5C%5Cn_%7B2%7D%20%3D%20%5Cfrac%7B1.85%20L%20%5Ctimes%209.0%20mol%7D%7B2.25%20L%7D%5C%5C%3D%207.4%20mol)
Thus, we can conclude that there are 7.4 moles of helium gas present in a 1.85 liter container at the same temperature and pressure.
Answer:
0.665 moles of CO₂
Explanation:
The balance chemical equation for the combustion of Ethane is as follow:
2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O
Step 1: <u>Calculate moles of C₂H₆ as;</u>
Moles = Mass / M.Mass
Putting values,
Moles = 10.0 g / 30.07 g/mol
Moles = 0.3325 moles
Step 2: <u>Calculate Moles of CO₂ as;</u>
According to balance chemical equation,
2 moles of C₂H₆ produced = 4 moles of CO₂
So,
0.3325 moles of C₂H₆ will produce = X moles of CO₂
Solving for X,
X = 0.3325 mol × 4 mol ÷ 2 mol
X = 0.665 moles of CO₂