I am a mental with 28 electrons

A balloon contains 0.140 molmol of gas and has a volume of 2.78 LL . If an additional 0.152 molmol of gas is added to the balloo

levacccp [35]

Answer:

The final volume will be 5.80 L

Explanation:

Step 1: Data given

Number of moles gas = 0.140 moles

Volume of gas = 2.78 L

Number of moles added = 0.152 moles

Step 2: Calculate the final volume

V1/n1 = V2/n2

⇒ with V1 = the initial volume = 2.78 L

⇒ with n1 = the initial number of moles = 0.140 moles

⇒ with V2 = The new volume = TO BE DETERMINED

⇒ with n2 = the new number of moles = 0.140 + 0.152 = 0.292 moles

2.78/0.140 = V2 /0.292

V2 = 5.80 L

The final volume will be 5.80 L

8 0

3 years ago

Bronze is an alloy made of mostly copper (Cu) and tin (Sn). What type of bond forms bronze?

Snezhnost [94]

Answer:

A. Metallic bond

Explanation:

Think about it: copper and tin are both common metals. That's how we know it's a metallic bond!

Why not B: Covalent bonds are between two nonmetals.

Why not C: Ionic bonds are between a nonmetal and a metal.

Why not D: Paired bond isn't a common phrase in chemistry.

6 0

3 years ago

Which statement best describes the weather shown by the purple combination of semicircles and triangles on a line on a weather m

BigorU [14]

Answer:

D

Explanation:

Meteorologists use this symbol to show that the front is a stationary front.

7 0

2 years ago

Read 2 more answers

A mouse is placed in a sealed chamber with air at 769.0 torr. This chamber is equipped with enough solid KOH to absorb any CO2 a

svlad2 [7]

<u>Answer:</u> The amount of oxygen gas consumed by mouse is 0.202 grams.

<u>Explanation:</u>

We are given:

Initial pressure of air = 769.0 torr

Final pressure of air = 717.1 torr

Pressure of oxygen = Pressure decreased = Initial pressure - Final pressure = (769.0 - 717.1) torr = 51.9 torr

To calculate the amount of oxygen gas consumed, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 51.9 torr

V = Volume of the gas = 2.20 L

T = Temperature of the gas = 292 K

R = Gas constant = $62.364\text{ L. Torr }mol^{-1}K^{-1}$

n = number of moles of oxygen gas = ?

Putting values in above equation, we get:

$51.9torr\times 2.20L=n\times 62.364\text{ L. Torr }mol^{-1}K^{-1}\times 292K\\\\n=\frac{51.9\times 2.20}{62.364\times 292}=0.0063mol$

To calculate the mass from given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of oxygen gas = 0.0063 moles

Molar mass of oxygen gas = 32 g/mol

Putting values in above equation, we get:

$0.0063mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.0063mol\times 32g/mol)=0.202g$

Hence, the amount of oxygen gas consumed by mouse is 0.202 grams.

5 0

2 years ago

When the equation __H2O2 --> __H2O + __O2 Is completely balanced, the sum of all the coefficients will be A) 5 B) 8 C) 3 D) 4

kkurt [141]

Answer:

A)5

Explanation:

2H2O2 --> 2H2O + 1O2

2+2+1=5

sum=5

8 0

3 years ago