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3 years ago

2. Which set of numbers have a least common

Mathematics

1 answer:

Dafna11 [192]3 years ago

6 0

Answer:

Step-by-step explanation:

Multiples of 16:

16, 32, 48, 64, 80

Multiples of 20:

20, 40, 60, 80, 100.

Here are the options verified:

A. 4 and 20. Incorrect. It takes a while to get to 80 by 4's.
B. 8 and 10. Incorrect. Same thing goes with A, but with 8's.
C. 16 and 20. Correct.
D. 12 and 40. Incorrect. 12 is not a multiple of 80.

Option C is your answer.

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24x^3y^2-16x^2y^3÷8xy

jok3333 [9.3K]

Answer:

24x 3 y 2 −2x 3 y 4

Step-by-step explanation:

thats the answer

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3 years ago

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Determine the x- and y- intercepts for the graph defined by the given equation. y = 7x + 3

pantera1 [17]

Answer:

intercept is 3

X intercept is -3/7

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4 years ago

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Given that the diameter of Circle A is 6 cm , and the radius of Circle B is 18 cm , what can be concluded about the two circles?

ELEN [110]

Answer:

The radius of circle B is 6 times greater than the radius of circle A

The area of circle B is 36 times greater than the area of circle A

Step-by-step explanation:

we have

Circle A

$D=6\ cm$

The radius of circle A is

$r=6/2=3\ cm$ -----> the radius is half the diameter

Circle B

$r=18\ cm$

Compare the radius of both circles

$3\ cm< 18\ cm$

$18=6(3)$

The radius of circle B is six times greater than the radius of circle A

Remember that , if two figures are similar, then the ratio of its areas is equal to the scale factor squared

All circles are similar

In this problem the scale factor is 6

$6^{2}=36$

therefore

The area of circle B is 36 times greater than the area of circle A

8 0

3 years ago

Write as a single term: cos(2x) cos(x) + sin(2x) sin(x)

GREYUIT [131]

Answer: cos(x)

Step-by-step explanation:

We have

sin ( x + y ) = sin(x)*cos(y) + cos(x)*sin(y) (1) and

cos ( x + y ) = cos(x)*cos(y) - sin(x)*sin(y) (2)

From eq. (1)

if x = y

sin ( x + x ) = sin(x)*cos(x) + cos(x)*sin(x) ⇒ sin(2x) = 2sin(x)cos(x)

From eq. 2

If x = y

cos ( x + x ) = cos(x)*cos(x) - sin(x)*sin(x) ⇒ cos²(x) - sin²(x)

cos (2x) = cos²(x) - sin²(x)

Hence:The expression:

cos(2x) cos(x) + sin(2x) sin(x) (3)

Subtition of sin(2x) and cos(2x) in eq. 3

[cos²(x)-sin²(x)]*cos(x) + [(2sen(x)cos(x)]*sin(x)

and operating

cos³(x) - sin²(x)cos(x) + 2sin²(x)cos(x) = cos³(x) + sin²(x)cos(x)

cos (x) [ cos²(x) + sin²(x) ] = cos(x)

since cos²(x) + sin²(x) = 1

8 0

3 years ago

Find all values of x in the interval [0,2π] that satisfy the equation sin2x=cosx. enter your answers as a list of numbers separa

yuradex [85]

$\sin(2x) = \cos(x) \\ 2 \sin(x) \cos(x) = \cos(x) \\ \cos(x) (2 \sin(x) - 1) = 0$
so
$\cos(x) = 0 > > > x = \frac{\pi}{2} + k\pi \\ \sin(x) = \frac{1}{2} > > > x = \frac{\pi}{6} + 2k\pi \\ or \: x = \frac{5\pi}{6} + 2k\pi$
$x = \frac{\pi}{2} or \frac{3\pi}{2} \\ x = \frac{\pi}{6} or \frac{5\pi}{6}$

6 0

3 years ago