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shusha [124]
3 years ago
11

Match the following: ​

Physics
2 answers:
sveta [45]3 years ago
6 0

Answer:

:))

Explanation:

Photovataic Solar Panels= Turn Sunlight into Electricity

Thermal Solar Panels= Turn Sunlight into Heat

Wind Turbines= Turn the Force of Wind into Electricity

Geothermal Stations= Use the Geothermal heat to generate electricity and to hear houses

Hydropower Stations= Turn the Force of Falling Water into Electricity

Tips:

Thermal is heat

Hydro is water/H2O

Geo is Gen(erate)

Mumz [18]3 years ago
4 0

Answer:

I matched the answers you requested above

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A long solenoid consists of 1700 turns and has a length of 0.75 m.The current in the wire is 0.48 A. What is the magnitude of th
Travka [436]

Answer:

1.37 ×10^-3 T

Explanation:

From;

B= μnI

μ = 4π x 10-7 N/A2

n= number of turns /length of wire = 1700/0.75 = 2266.67

I= 0.48 A

Hence;

B= 4π x 10^-7 × 2266.67 ×0.48

B= 1.37 ×10^-3 T

4 0
4 years ago
If the lily pads are spaced 2.4 m apart and Ferdinand jumps with a speed of 5 m/s taking 0.6 s to go from lily pad to lily pad,
Zina [86]

Answer:

36.87^{\circ}

Explanation:

v = Velocity of Ferdinand = 5 m/s

\theta = Angle of jump

T = Time taken = 0.6 s

R = Distance between lily pads = 2.4 m

Horizontal range is given by

R=v_xT\\\Rightarrow R=vcos\theta T\\\Rightarrow cos\theta=\dfrac{R}{vT}\\\Rightarrow \theta=cos^{-1}\dfrac{R}{vT}\\\Rightarrow \theta=cos^{-1}\dfrac{2.4}{5\times 0.6}\\\Rightarrow \theta=36.87^{\circ}

The angle at which Ferdinand make each of his jumps is 36.87^{\circ}

8 0
3 years ago
Football player A has a mass of 210 pounds and is running at a rate of 5.0mi/hr. He collides with player B. Player B has a mass
LuckyWell [14K]
The answer is b.) the momentum before the collision is greater than the momentum after the collision
8 0
3 years ago
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Can some answer 7 a and b please
pav-90 [236]

Answer:

a.After 15 second Mr Comer's speed =  1.7 m/s

b.Distance travelled by Mr.Comer in 15 seconds  =   18.75\ m

Explanation:

a. Lets recall our first equation of motion V_{f} =V_{i} + at

Now we know that V_{i} = 0.8m/s , a = 0.06\ m/s^2 and

t = 15 \ sec

Plugging the values we have.

V_{f} =V_{i} + at

V_{f} =0.8 + 0.06 \times 15

V_{f} =0.8+ 0.9

V_{f} =1.7 m/s

Then Mr.Comer's speed after 15 sec = 1.7ms^-1

b.

Lets find the distance and recall our third equation of motion.

V_{f} ^2-V{i}^2 = 2as

So s = distance covered.

Dividing both sides with 2a we have.

\frac{V_{f} ^2-V{i}^2}{2a} = 2as

Plugging the values.

\frac{(1.7)^2-(0.8)^2}{2\times0.06} = 2as

s= 18.75\ m

So Mr.Comer will travel a distance of s= 18.75\ m.

4 0
3 years ago
Se um corpo 1 está em movimento em relação a um corpo 2, e se o corpo 2 está em repouso em relação a um corpo 3, pode-se afirmar
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Yo habla ingles no espanol
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