Answer:
Thus, the initial velocity of the bullet is 507.5 m/s.
Explanation:
mass of bullet, m = 0.0085 kg
mass of block, M = 0.99 kg
Height raised, h = 0.95 m
Let the initial velocity of bullet is u and the final velocity of block and bullet system is v.
Use conservation of energy
Potential energy of bullet bock system = kinetic energy of bullet block system
Now use conservation of linear momentum
mu = (M+m) v
0.0085 x u = (0.99 + 0.0085) x 4.32
0.0085 u = 4.314
u = 507.5 m/s
Thus, the initial velocity of the bullet is 507.5 m/s.
