I am almost positive that it was, ISSAC NEWTON
Rocket thrust equation
= ( mass flow rate of fuel burnt ) X (Velocity of gas ejected ) + ( Exit Pressure - Outdoor Pressure ) X ( Area of exhaust )
In this case, we can assume the exit pressure = outdoor pressure and since area of exhaust is not given, it can be assumed to be negligible.
In this case, by Newton 3rd’s law,
Force exerted by gas on rocket
= Force exerted by rocket on gas
= (10kg/s) X (5 x 10^3 m/s)
= 5 x 10^4 N
Answer:
F = 17.3 kN
Explanation:
The normal force must support the weight of the car plus provide for the needed centripetal acceleration.
F = m(g + v²/R ) = 1000(9.8 + 15²/30) = 17,300
