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larisa86 [58]
3 years ago
7

What are the principles that no

Physics
1 answer:
solmaris [256]3 years ago
5 0

Answer:

There are seven principles that form the content grounds of our teaching framework:

Non-maleficence. ...

Beneficence. ...

Health maximisation. ...

Efficiency. ...

Respect for autonomy. ...

Justice. ...

Proportionality.

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List the steps you would use to reach one of your personal growth goals.
Zinaida [17]
Im not sure, but here are a few of mine : Learn to be silent, and listen, take massive action and be proactive, listen, focus, and lastly, persist. Hope this helped! (:
6 0
4 years ago
Currents in the ocean are caused by differences in water density. Colder, denser water tends to
irinina [24]

Answer:

The answer is D.

Explanation:

Just like how cold air falls and warm air rises the same is with water.

Also the places with the coldest water is the north and south pole. The equator is relatively always warm so yeah.

5 0
3 years ago
Read 2 more answers
What is the maximum number of f orbitals that are possible in a given shell?
Lemur [1.5K]

Answer: seven f orbitals

Explanation:

7 0
3 years ago
wo kids are on a seesaw. The one on the left has a mass of 75 kg and is sitting 1.5 m from the pivot point. The one on the right
Anastaziya [24]

Answer:

4.5 Nm (Anticlockwise)

Explanation:

Let the 75 kg kid is sitting at the left end and the 60 kg kid is sitting on the right end.

Anticlockwise Torque = 75 x 1.5 = 112.5 Nm

clockwise Torque = 60 x 1.8 = 108 Nm

Net torque = Anticlockwise torque - clockwise torque

Net Torque = 112.5 - 108 = 4.5 Nm (Anticlockwise)

5 0
3 years ago
The position of a particle moving along an x axis is given by x = 14.0t2 - 2.00t3, where x is in meters and t is in seconds. det
Mumz [18]

a) x = 14t^{2} -2t^{3}

at t = 5s

x = 14*5^{2} -2*5^{3} = 14*25 - 2*125 = 350 - 250 = 100 m

b) v = \frac{dx}{dt}

       = 28t - 6t^2

at t = 5 s

v = 28*5-6*25 = 140 - 150 = -10 m/s

c) a = \frac{dv}{dt}

     = 28 - 12t

at t = 5 s

a = 28 -12*5= 28-60= -32 m/s^2

d) At maximum positive coordinate velocity = 0

So, 0 = 28t - 6t^2

         t = \frac{28}{6} = \frac{14}{3} = 4.66 s

  At t = 4.66 s

   X = 14 * 4.66^2 - 2* 4.66^3 = 202.39  m

e) At t = 4.66 s

f) At maximum positive velocity a = 0

   0=28-12t

   t = \frac{28}{12} = \frac{7}{3} = 2.33 s

At t = 2.33 s

V = 28*2.33- 6*2.33^2= 32.67 m/s

g) t = 2.33 s

h) When particle is not moving v = 0

So 0= 28t - 6 t^2

 t = \frac{28}{6} = 4.66 seconds

At t = 4.66 s

a = 28 - 12 * 4. 66 = -27.93m/s^2

i) At t = 0s, X =0m

       t = 5s, X = 100m

So, Displacement = 100m

Velocity = \frac{Displacement}{Time}  = \frac{100}{5} = 20m/s

8 0
3 years ago
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