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Kaylis [27]
3 years ago
7

Write a method which prevents ice from melting quickly.​

Physics
1 answer:
Gnom [1K]3 years ago
4 0

Answer:

blocks of ice are usually covered with cloth or sawdust while being stored

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Two in-phase loudspeakers that emit sound with the same frequency are placed along a wall and are separated by a distance of 8.0
zloy xaker [14]

Answer: 278\ Hz

Explanation:

Given

Distance between two speakers is 8 m

Man is standing 12 away from the wall

When the person moves 3 parallel to the wall

the parallel distances from the speaker become 4+3, 4-3

Now, the difference of distances from the speaker is

\Delta d=\sqrt{12^2+(4+3)^2}-\sqrt{12^2-(4-3)^2}\\\Delta d=1.85\ m

Condition for destructive interference is

\Delta d=(2n-1)\dfrac{\lambda }{2}=(2n-1)\dfrac{\nu }{2f}\\\\\Rightarrow f=(2n-1)\dfrac{v}{2\Delta d}

for second destructive interference; n=2

\Rightarrow f=(2\times 2-1)\dfrac{343}{2\times 1.85}=278.10\approx 278\ Hz

4 0
3 years ago
A coil of wire with 60 turns lies on the plane of the page, and a uniform magnetic field points into the page with a strength of
baherus [9]

Answer:

0.85V

Explanation:

The emf is calculated by using the Lenz's Law

\epsilon=-\frac{\Delta\Phi_B}{\Delta t}

But for this case we have that the magnetic field is constant. Hence we have

\epsilon=-\frac{B(A_{2}-A_{1})}{t_2-t_1}=-\frac{(1.10T)(0.270m^{2}-0.89m^{2})}{0.8s}\\\\\epsilon=0.85V

where we have taken that the intial time is t1=0

I hope this is useful for you

regards

4 0
3 years ago
An airplane is accelerating forward due to a force of 3320 newtons acting
Darya [45]

Two opposite forces generate a force whose magnitude is the difference of the two magnitudes, and whose direction is the same of the strongest one.

We have 3320 newtons forward, and 550 backwards.

So, the net force is forward, and has magnitude 3320-550=2770

5 0
3 years ago
A hot-air balloon is ascending at the rate of 10 m/s and is 74 m above the ground when a package is dropped over the side. (a) H
Reika [66]

Answer:

The answer to your question is:

a)  t1 = 2.99 s ≈ 3 s

b)  vf = 39.43 m/s

Explanation:

Data

vo = 10 m/s

h = 74 m

g = 9.81 m/s

t = ?   time to reach the ground

vf = ?   final speed

a)    h = vot + (1/2)gt²

     74 = 10t + (1/2)9.81t²

     4.9t² + 10t -74 = 0                  solve by using quadratic formula

   

   t = (-b ± √ (b² -4ac) / 2a

   t = (-10 ± √ (10² -4(4.9(-74) / 2(4.9)

   t = (-10 ± √ 1550.4 ) / 9.81

  t1 = (-10 + √ 1550.4 ) / 9.81               t2 = (-10 - √ 1550.4 ) / 9.81

  t1 = (-10 ± 39.38 ) / 9.81                    t2 = (-10 - 39.38) / 9.81

   t1 = 2.99 s ≈ 3 s                               t2 = is negative then is wrong there are

                                                                   no negative times.

b) Formula vf = vo + gt

                  vf = 10 + (9.81)(3)

                  vf = 10 + 29.43

                  vf = 39.43 m/s

4 0
3 years ago
2 m3 of an ideal gas are compressed from 100 kPa to 200 kPa. As a result of the process, the internal energy of the gas increase
rosijanka [135]

Answer:

work done is -150 kJ

Explanation:

given data

volume v1 = 2 m³

pressure p1 = 100 kPa

pressure p2 = 200 kPa

internal energy = 10 kJ

heat is transferred  = 150 kJ

solution

we know from 1st law of thermodynamic is

Q = du +W    ............1

put here value and we get

-140 = 10 + W

W = -150 kJ

as here work done is -ve so we can say work is being done on system

3 0
3 years ago
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