Answer:
h_f = 15 ft, so option A is correct
Explanation:
The formula for head loss is given by;
h_f = [10.44•L•Q^(1.85)]/(C^(1.85))•D^(4.8655))
Where;
h_f is head loss due to friction in ft
L is length of pipe in ft
Q is flow rate of water in gpm
C is hazen Williams constant
D is diameter of pipe in inches
We are given;
L = 1,800 ft
Q = 600 gpm
C = 120
D = 8 inches
So, plugging in these values into the equation, we have;
h_f = [10.44*1800*600^(1.85)]/(120^(1.85))*8^(4.8655))
h_f = 14.896 ft.
So, h_f is approximately 15 ft
Answer:
Explanation:
Obtain the following properties at 6MPa and 600°C from the table "Superheated water".

Obtain the following properties at 10kPa from the table "saturated water"

Calculate the enthalpy at exit of the turbine using the energy balance equation.

Since, the process is isentropic process 

Use the isentropic relations:

Calculate the enthalpy at isentropic state 2s.

a.)
Calculate the isentropic turbine efficiency.

b.)
Find the quality of the water at state 2
since
at 10KPa <
<
at 10KPa
Therefore, state 2 is in two-phase region.

Calculate the entropy at state 2.

Calculate the rate of entropy production.

since, Q = 0

Answer:
c
Explanation:
This is because many things, such as pcs, over heat
Answer:
You can look it up
Explanation: if you don't know what it is look it up on .